A simple pendulum of length 1.5m has a bob of mass of 2.0kg, then the period for the small oscillations would be 2.456 s.
<h3>What is the frequency?</h3>
It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.
The frequency of a pendulum is the reciprocal of the time period can be given by the following relation,
f = 1/T
As given in the problem A simple pendulum of length 1.5m has a bob of mass of 2.0kg.
The formula for the time period for the pendulum,
T = 2π√L/g
=2π√1.5/9.81
=2.456 s
Thus, the period for the small oscillations would be 2.456 s.
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Answer:
A.) 12.5 J
B.) 12.5 J
C.) 7.1 m/s
Explanation:
Given that a 0.5 kg object, initially at rest, is pulled to the right along a frictionless horizontal surface by a constant horizontal force of 25 N for a distance of 0.5m.
a. What is the work done by the force?
Work done = force × distance
Work done = 25 × 0.5
Work done = 12.5 J
b. What is the change in the kinetic energy of the block?
Work done = energy
Change in Kinetic energy = work done
Change in kinetic energy = 12.5 J
c. What is the speed of the block after the force is removed?
Kinetic energy = 1/2mV^2
12.5 = 1/2 × 0.5 × V^2
25 = 0.5V^2
V^2 = 25/0.5
V^2 = 50
V = 7.1 m/s
The short answer is "it is a very intense star."
Answer:
a) d = 7.62 10⁻⁶ m, b) l = 3.25 10⁴ m
Explanation:
Resistance is expressed by the formula
R = ρ l / A (1)
density is defined by
density = m / V
the volume of a wire is the cross section by the length
V = A l
we substitute
density = m / A l
A = m / density l
we substitute in 1
R = ρ l density l / m
R =ρ density l² / m
l = √ (R m /ρ density)
let's calculate the cable length
l = √(11.7 13.5 10⁻³ / (1.68 10⁻⁸ 8.9 10³))
l = √(10.56 10⁸)
l = 3.25 10⁴ m
now we can find the cable diameter with the density equation
A = m / density l
A = 13.5 10⁻³ / (8.9 10³ 3.25 10⁴)
A = 4,557 10⁻¹¹ m²
the area of the circle is
A = π r² = π d² / 4
d = √ (4A /π)
d = √ (4 4,557 10⁻¹¹/π)
d = 7.62 10⁻⁶ m
There are 1,000,000 micro seconds in one second so multiple 136.8 by 1000000 and you'll get 136,800,000 Tera calculations per second.
