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Talja [164]
2 years ago
15

An AC generator consists of 6 turns of wire. Each turn has an area of 0.040 m2. The loop rotates in a uniform field (B = 0.20 T)

at a constant frequency of 50 Hz. What is the maximum induced emf?
Physics
1 answer:
Alja [10]2 years ago
5 0

Answer:

The maximum induced emf is 15.08 V

Explanation:

Given;

number of turns of the generator, N = 6 turns

area of the loop, A = 0.04 m

magnetic field of the loop, B = 0.2 T

frequency of loop, f = 50 Hz

The  maximum induced emf is given by;

E = NBAω

Where;

ω is the angular speed = 2πf

E = NBA(2πf)

E = 6 x 0.2 x 0.04 x (2 x 3.142 x 50)

E = 15.08 V

Therefore, the maximum induced emf is 15.08 V

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Answer:

g_x = 3.0 m / s^2

Explanation:

Given:

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- Time taken for 11 oscillations t = 19.0 s

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                                 T  = 2*pi*sqrt(k / m )    ...... 1

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                                 F_net = k*x - m*g_x = 0

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- substitute Eq 2 into Eq 1:

                                  2*pi / T = sqrt ( g_x / x )

                                   g_x = (2*pi / T )^2 * x

- Evaluate g_x:

                                  g_x = (2*pi / (19 / 11) )^2 * 0.226

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3 0
3 years ago
A coin is dropped in a 15.0 m deep well.
labwork [276]

Answer:

t = 1.75

t = 0.04

Explanation:

a)

For part 1 we want to use a kenamatic equation with constant acceleration:

X = 1/2*a*t^2

isolate time

t = sqrt(2X / a)

Plugin known variables. Acceleration is the force of gravity which is 9.8 m/s^2

t = sqrt(2*15m / 9.8m/s^2)

t = 1.75 s

b)

The speed of sound travels at a constant speed therefore we don't need acceleration and can use the equation:

v = d / t

isolate time

t = d / v

plug in known variables

t = 15m / 340m/s

t = 0.04 s

7 0
2 years ago
A. An automobile mass is 3.5 x103 kg. If the forward thrust (Fnet)
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Answer:

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If a car travels 600m west in 25 seconds, what is its velocity?
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v =  \frac{ \:the covered distance}{time} \\

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v = 24 \:  \frac{m}{s} \\

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Explanation:

4 0
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