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MAVERICK [17]
3 years ago
13

WILL GIVE BRAINLIEST

Chemistry
1 answer:
Alex777 [14]3 years ago
3 0

For the first one, you have to find one that has both a metal and a nonmetal in it, plus potassium. Bonds between nonmetals are called covalent because they share electrons and a bond between a metal and a nonmetal is an ionic bond because they exchange electrons.

Potassium chloride is KCl. Only an ionic bond.

Potassium hydride is KH. Only an ionic bond.

Potassium nitrate is KNO3. There we go, that has a covalent bond between the nitrogen and oxygen, and an ionic bond between potassium and the nitrogen and oxygen.

For the second one, potassium chloride is the answer because the other three also have covalent bonds. Chloride is the only one that isn't a compound.

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In the first step of the reaction, which compound is the limiting reagent: sodium hydroxide or the nucleophile
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Since the nucleophile is the actual attacking molecule or molecule that starts the reaction and allows for further steps in the mechanism to occur, it is the limiting reagent, as based on the amount of the nucleophile you have, the reaction will tend to proceed until you run out. The excess would be the sodium hydroxide, it is union part of the solution.
5 0
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A mole of Big Macs stacked would reach from the earth to the moon and back how many times?
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A mol=6.02*10^23
so
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divide both sides by 2
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divide both sides by 6.02
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825583769024485.8
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6 0
3 years ago
How many joules of heat are absorbed when 73 g water are heated from 30*C to 43*C? *
stepladder [879]

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3966.82 J

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6 0
3 years ago
Read 2 more answers
In an accident, a solution containing 2.5 kg of nitric acid was spilled. Two kilograms of Na2CO3 was quickly spread on the area
storchak [24]

First we must write a balanced chemical equation for this reaction

Na_2CO_3 _(_a_q_)+ 2HNO_3_(_a_q_) \implies 2NaNO_3_(_s_) + CO_2_(_g_) + H_2O_(_l_)

The mole ratio for the reaction between HNO_3 and Na_2CO_3 is 1:2. This means 1 moles of Na_2CO_3 will neutralize 2 moles HNO_3. Now we find the moles of each reactant based on the mass and molar mass.

2500g HNO_3 \times \frac{mol}{63.01g\ HNO_3} = 39.67 mol\ HNO_3

2000g\ Na_2CO_3 \times \frac{mol}{105.99g \ Na_2CO_3} = 18.87 mol\ Na_2CO_3

\frac{18.87 mol Na_2CO_3}{39.67\ HNO_3} = \frac{1 molNa_2CO_3}{2 mol HNO_3}

The Na_2CO_3 was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.

4 0
3 years ago
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