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allsm [11]
3 years ago
6

Which of the following universal forces is the weakest? 

Physics
2 answers:
My name is Ann [436]3 years ago
5 0
Well, electric and magnetic are actually the same in nature (as basic force in the Universe). The four, in decreasing order of strength, are:
Strong nuclear, Weak nuclear, Electric/Magnetic (in roughly the same range) and Gravitational (much weaker than Electric/Magnetic -- a magnet less than 1 kg beats Earth which is quite a lot of gigatons, roughly)
Westkost [7]3 years ago
3 0

Answer:

Option (B)

Explanation:

The gravitational force is usually defined as the force of attraction that occurs due to the presence of the object's mass. The mass of the object and the force of gravity is directly proportional to each other. At the atomic as well as at the subatomic levels, this gravitational force of gravity is comparatively so weak because the masses of these atoms, subatomic particles are extremely very small. This force has a strength of about 10^-40 and this far smaller in comparison to the strength of electromagnetism.

On the other hand, the other universal forces such as the electric force, magnetic and strong nuclear force are very much stronger than the gravitational force. The nuclear force is strongest of all, where it is 100  times stronger than the electromagnetic force and approximately 10^36 times stronger than the gravitational force.

Thus, the correct answer is option (B).

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A flat uniform circular disk (r= 2.00m,
dusya [7]

Incomplete question.The Complete question is here

A flat uniform circular disk (radius = 2.00 m, mass = 1.00 ✕ 102 kg) is initially stationary. The disk is free to rotate in the horizontal plane about a friction less axis perpendicular to the center of the disk. A 40.0-kg person, standing 1.25 m from the axis, begins to run on the disk in a circular path and has a tangential speed of 2.00 m/s relative to the ground.

a.) Find the resulting angular speed of the disk (in rad/s) and describe the direction of the rotation.

b.) Determine the time it takes for a spot marking the starting point to pass again beneath the runner's feet.

Answer:

(a)ω = 1 rad/s

(b)t = 2.41 s

Explanation:

(a) initial angular momentum = final angular momentum  

0 = L for disk + L............... for runner

0 = Iω² - mv²r ...................they're opposite in direction

0 = (MR²/2)(ω²) - mv²r ................where is ω is angular speed which is required in part (a) of question

0 = [(1.00×10²kg)(2.00 m)² / 2](ω²) - (40.0 kg)(2.00 m/s)²(1.25 m)

0=200ω²-200

200=200ω²

ω = 1 rad/s

b.)

lets assume the "starting point" is a point marked on the disk.

The person's angular speed is  

v/r = (2.00 m/s) / (1.25 m) = 1.6 rad/s

As the person and the disk are moving in opposite directions, the person will run part of a revolution and the turning disk would complete the whole revolution.

(angle) + (angle disk turns) = 2π

(1.6 rad/s)(t) + ωt = 2π

t[1.6 rad/s + 1 rad/s] = 2π

t = 2.41 s

6 0
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Explanation:

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Difference between dynamo and generator
QveST [7]

Answer:

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