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Airida [17]
2 years ago
11

What class of organic product results when 1-heptyne is treated with a mixture of mercuric acetate in aqueous sulfuric acid, and

then HOCH2CH2OH with catalytic sulfuric acid

Chemistry
1 answer:
crimeas [40]2 years ago
5 0

Answer:

2-methyl-2-pentyl-1,3-dioxolane

Explanation:

In this case, we have two reactions:

First reaction:

1-heptyne + mercuric acetate -------> Compound A

Second reaction:

Compound A + HOCH2CH2OH -------> Compound C

<u>First reaction</u>

In the first reaction, we have as a main functional group a triple bond. We have to remember that mercuric acetate in sulfuric acid will produce a ketone. The carbonyl group (C=O) would be placed in the most substituted carbon of the triplet bond (in this case, carbon 2). With this in mind, we will have as a product: heptan-2-one. (See figure 1).

<u>Second reaction</u>

<u />

In this reaction, we have as reagents:

-) Heptan-2-one

-) Ethylene-glycol HOCH_2CH_2OH

-) Sulfuric acid H_2SO_4

When we put ethylene-glycol with a ketone or an aldehyde we will form a cyclic acetal. In this case, this structure would be formed on carbon 2 forming 2-methyl-2-pentyl-1,3-dioxolane. (See figure 2).

I hope it helps!

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6 0
3 years ago
What gas is used in freezers and fridges? ​
natta225 [31]

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Chloro-Flouro-Carbon

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7 0
3 years ago
What is Artificial selection???
kati45 [8]

Answer:

The process of selection conducted under human direction.

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For example, by allowing only like individuals to breed, breeders have created the great variety of dog breeds and crop plants

7 0
3 years ago
What is the total number of calories of heat energy absorbed when 10 grams of water is vaporized at its normal boiling point
Darya [45]

<u>Answer:</u> The amount of energy absorbed by water is 5390 Calories

<u>Explanation:</u>

To calculate the amount of heat absorbed at normal boiling point, we use the equation:

q=m\times L_{vap}

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q = amount of heat absorbed = ?

m = mass of water = 10 grams

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Putting values in above equation, we get:

q=10g\times 539Cal/g=5390Cal

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6 0
3 years ago
A gas has a volume of 3L at 200 kPa. What will its volume be if the pressure is changed to 500 kPa?
marta [7]

Answer:

6L

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then it would be;

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5L per 400kPa

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that's how i'd work it out in my head, hope it helps, but not sure though!

5 0
3 years ago
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