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Airida [17]
3 years ago
11

What class of organic product results when 1-heptyne is treated with a mixture of mercuric acetate in aqueous sulfuric acid, and

then HOCH2CH2OH with catalytic sulfuric acid

Chemistry
1 answer:
crimeas [40]3 years ago
5 0

Answer:

2-methyl-2-pentyl-1,3-dioxolane

Explanation:

In this case, we have two reactions:

First reaction:

1-heptyne + mercuric acetate -------> Compound A

Second reaction:

Compound A + HOCH2CH2OH -------> Compound C

<u>First reaction</u>

In the first reaction, we have as a main functional group a triple bond. We have to remember that mercuric acetate in sulfuric acid will produce a ketone. The carbonyl group (C=O) would be placed in the most substituted carbon of the triplet bond (in this case, carbon 2). With this in mind, we will have as a product: heptan-2-one. (See figure 1).

<u>Second reaction</u>

<u />

In this reaction, we have as reagents:

-) Heptan-2-one

-) Ethylene-glycol HOCH_2CH_2OH

-) Sulfuric acid H_2SO_4

When we put ethylene-glycol with a ketone or an aldehyde we will form a cyclic acetal. In this case, this structure would be formed on carbon 2 forming 2-methyl-2-pentyl-1,3-dioxolane. (See figure 2).

I hope it helps!

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Consider the sodium borohydride reduction of camphor to isoborneol. A reaction was performed in which 1.600 g of camphor was red
ki77a [65]

Answer:

62.5%

Explanation:

Number of moles of camphor reacted= 1.6g/152.23 g/mol = 0.011 moles

Since the reaction is 1:1,  then 0.011 moles of isoborenol is also produced.

Theoretical yield of isoborenol produced = 154.25 g/mol * 0.011 moles = 1.698 g

% yield = actual yield/theoretical yield * 100

% yield =  1.062 g/1.698 g * 100

% yield =  62.5%

6 0
2 years ago
How many grams of C8H18<br> is in 405,576.398 mL
nevsk [136]

Molarity X \frac{0.762 mol}{05.576398 L} = Mass is the of C_8H_1_8 is in 405,576.398 mL.

<h3>What is molarity?</h3>

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

Given data:

Molar mass of  C_8H_1_8 = 0.762 mol

Volume of solution = 405,576.398 mL = 405,576.398 mL/1000 = 405.576398 L

Solution:

Step 1: Calculating  moles of C_8H_1_8

• Molarity =\frac{\;Moles \;of \;solute}{\;Volume \;of \;solution \;in \;litre}

• Putting the value in the given formula

• Moles of solute C8H18 = \frac{\;Mass}{\;Molar \;molar \;mass}

• Moles of solute C8H18 = \frac{\;Mass}{0.762 mol}

Now,

Molarity =\frac{\;Moles \;of \;solute}{\;Volume \;of \;solution \;in \;litre}

Molarity =\frac{\frac{\;Mass}{0.762 mol}}{\;Volume \;of \;solution \;in \;litre}

Molarity =\frac{\frac{\;Mass}{0.762 mol}}{405.576398 L}

Molarity X \frac{0.762 mol}{05.576398 L} = Mass

Hence, Molarity X \frac{0.762 mol}{05.576398 L} = Mass is the of C_8H_1_8 is in 405,576.398 mL.

Learn more about molarity here:

brainly.com/question/2817451

#SPJ1

4 0
2 years ago
3) What are the three types of sedimentary rocks?
astraxan [27]

Answer:

clastic, organic, and chemical

8 0
3 years ago
The ph scale for acidity is defined by ph=−log10[h+] where [h+]is the concentration of hydrogen ions measured in moles per liter
Leokris [45]

The question is incomplete.

The complete question probably is

The pH scale for acidity is defined by pH = − log₁₀[H⁺] where [H⁺] is the concentration of hydrogen ions measured in moles per liter (M). A solution has a pH of 2.55. Find the hydrogen ion concentration.

Answer: -

0.003 M

Explanation: -

pH = − log₁₀[H⁺]

Thus the hydrogen ion concentration [H⁺] = 10^{-pH}

= 10^{-2.55}

= 0.003 M

7 0
3 years ago
Problem Page What kind of intermolecular forces act between a formaldehyde molecule and a hydrogen sulfide molecule? Note: If th
malfutka [58]

Answer:

Hydrogen Bonding

Explanation:

Formaldehyde, H2CO, has an oxygen atom which is quite electronegative that means it would attract any atom with a slightly positive charge. Hydrogen in the Hydrogen sulfide (H2S) is attracted by oxygen and hence hydrogen bonding can occur.

8 0
3 years ago
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