Answer:
I Think It's The Second One
Tell Me If I'm Wrong
Answer:
The heat required to melt 7.35 g of benzene at its normal melting point is 934.8 Joules.
The heat required to vaporize 7.35 g of benzene at its normal melting point is 2,893 Joules.
Explanation:
Mass of benzene = 7.35 g
Moles of benzene =
Heat fusion of benzene,
1) Heat required to melt 7.35 g of benzene at its normal melting point = Q
(1 kJ = 1000 J)
2) Heat vaporization of benzene,
Heat required to vaporize 7.35 g of benzene at its normal melting point = Q
(1 kJ = 1000 J)
Answer:
2.04 atm
Explanation:
The pressure of the gas can be found by using the equation of state for an ideal gas:
where
p is the gas pressure
V is the gas volume
n is the number of moles
R is the gas constant
T is the absolute temperature of the gas
For this gas we have:
n = 0.316 mol (moles)
V = 4.00 L (volume)
T = 315 K (absolute temperature)
(gas constant)
Therefore, the gas pressure is
One MOLE of hydrogen atoms contains the same number of atoms as the number of hydrogen molecules in one MOLE of hydrogen molecules, i.e., Avagadros number. However, one mole of hydrogen atoms has a mass of 1 gram while one MOLE of hydrogen molecules has a mass of 2 grams
Thank me later
Answer:
See-saw
Explanation:
To determine the molecular shape of BrF₄⁺, you need to
1.) Calculate the valence electrons of BrF₄⁺
----> Add the valence electrons of each individual atom
----> Take the positive charge into account (subtract 1 electron)
2.) Draw the Lewis Dot diagram of BrF₄⁺
----> Each bond has 2 electrons
----> Bromine can have an expanded octet
3.) Determine the molecular shape of BrF₄⁺