Answer is 0.7 g
Reason: Given: mass of Fe = 5.60 gWe know that, half life of Fe-53 = t1/2 (Fe-53) = 8.51 min.
Thus, after 25.53 mins, number of half life passed = 25.53/8.51= 3
Now, Amount left after first half life = 5.60g/2 = 2.80 g
Amount left after second half life = 2.80g/2 = 1.40 g
Amount left after third half-life = 1.40g/2 = 0.7g.
Answer:
Option E is correct. none of the above is correct
Explanation:
Step 1: Data given
Solid Iron (III) = Fe^3+
iron (III) oxide = Fe2O3
Molar mass Fe = 55.845 g/mol
Molar mass Fe2O3 = 159.69 g/mol
Step 2: The balanced equation:
4Fe + 3O2 → 2Fe2O3
4 moles of iron will need 2 moles of oxygen gas to fully react
⇒ This is false 4 moles of iron will need 3 moles of oxygen gas to fully react
B.12 moles of iron, if reacted completely, can produce 8 moles of iron (III) oxide.
⇒ This is false: When 12 moles of iron completely react, we can produce 12/2 = 6 moles of Fe2O3
C.9 moles of oxygen can produce 9 moles of Iron (III) oxide
⇒ This is false; 9 moles of O2 can produce 6 moles of Fe2O3
D.6 moles of oxygen can react completely to produce 6 moles of iron (III) oxide.
⇒ This is false 6 moles of O2 will react completely to produce 4 moles of Fe2O3
E.none of the above
D IS THE ANSWER TO YOUR QUESTION
Answer:
36.09% is the mass percent composition of calcium in calcium chloride
Explanation:
Mass percent is defined as one hundred times the ratio between the mass of a compound (In this case, Calcium), and the total mass of the sample:
<em>Mass Percent = Mass compound / Total mass of the sample × 100</em>
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Computing the values of the problem:
Mass Percent = 0.690g / 1.912g * 100
Mass percent =
<h3>36.09% is the mass percent composition of calcium in calcium chloride</h3>
Answer:
Phase changes typically occur when the temperature or pressure of a system is altered. When temperature or pressure increases, molecules interact more with each other. When pressure increases or temperature decreases, it's easier for atoms and molecules to settle into a more rigid structure.
Explanation:
Hope it helps UvU
