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3 years ago

Calcium solid is placed in a solution of iron (III) chloride producing calcium chloride and iron solid

Chemistry

1 answer:

mestny [16]3 years ago

6 0

Answer:

3Ca₍s₎ + 2FeCl₃ -------------------------------------------------------------> 3CaCl₂ + 2Fe₍s₎.

Explanation:

Iron(III) chloride is also known as Iron trichloride and it has the molar mass value of 162.2 g/mol and density of 2.9 g/cm³.

The balanced equation for the chemical reaction between solid calcium and iron (III) chloride is given below as:

3Ca₍s₎ + 2FeCl₃ -------------------------------------------------------------> 3CaCl₂ + 2Fe₍s₎.

This kind of chemical reaction is known as single displacement reaction or single replacement reaction. 

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What is the total number of joules of heat needed to change 300 g of water to

Mandarinka [93]

Answer:

6.78 × 10⁵ J

Explanation:

Step 1: Given and required data

Mass of water (m): 300 g

Latent heat of vaporization of water (ΔH°vap): 2260 J/g

Step 2: Calculate the heat (Q) required to vaporize 300 grams of water

We will use the following expression.

Q = ΔH°vap × m

Q = 2260 J/g × 300 g

Q = 6.78 × 10⁵ J

6.78 × 10⁵ Joule will be required to convert 300 g of water to steam at 100 °C.

3 0

3 years ago

A mole of cars stacked end to end would stretch back and forth across the United States how many times? Measured length of 1 car

vekshin1

Answer:

i am potato

Explanation:

4444141+5-45458/85*55474

3 0

3 years ago

Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid

Phoenix [80]

Answer:

pH = 8.0

Explanation:

First, we have to calculate the moles of NaOH.

$35.8 \times 10^{-3}L.\frac{0.020mol}{L} =7.2\times 10^{-4}mol$

Let's consider the balanced equation.

C₂H₄O₃ + NaOH ⇒ C₂H₃O₃Na + H₂O

The molar ratio C₂H₄O₃: NaOH: C₂H₃O₃Na is 1: 1: 1. So, when 7.2 × 10⁻⁴ moles of NaOH react completely with 7.2 × 10⁻⁴ moles of C₂H₄O₃ they form 7.2 × 10⁻⁴ moles of C₂H₃O₃Na.

The concentration of C₂H₃O₃Na is:

$\frac{7.2\times 10^{-4}mol}{60.8 \times 10^{-3}L} =0.012M$

C₂H₃O₃Na dissociates according to the following equation:

C₂H₃O₃Na(aq) ⇒ C₂H₃O₃⁻(aq) + Na⁺(aq)

C₂H₃O₃⁻ comes from a weak acid so it undergoes basic hydrolisis.

C₂H₃O₃⁻ + H₂O ⇄ C₂H₄O₃ + OH⁻

If we know that pKa for C₂H₄O₃ is 3.9, we can calculate pKb for C₂H₃O₃⁻ using the following expression:

pKa + pKb = 14

pKb = 14 -3.9 = 10.1

10.1 = -log Kb

Kb = 7.9 × 10⁻¹¹

We can calculate [OH⁻] using the following expression:

[OH⁻] = √(Kb.Cb) where Cb is the initial concentration of the base

[OH⁻] = √(7.9 × 10⁻¹¹ × 0.012M) = 9.7 × 10⁻⁷ M

Now, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log (9.7 × 10⁻⁷) = 6.0

pH + pOH = 14

pH = 14 - pOH = 14 - 6.0 = 8.0

7 0

3 years ago

What is the wavelength of a light wave with a frequency of 2.5 × 1014 Hz? A. 7.5 × 10-6 m B. 1.2 × 10-6 m C. 1.2 × 10-5 m D. 8.3

Likurg_2 [28]

Answer:

The right option is B

Explanation:

The frequency of the wave is given by the following formula:

$f = \dfrac{c}{\lambda}$

where,

f = frequency of the wave.

c = speed of the light.

λ = wavelength of the light.

$\lambda = \dfrac{c}{f}$

$\lambda = \dfrac{3\times10^{8}}{2.5\times10^{14}}$

$\lambda = 1.2 \times 10^{-6}$

Therefore the correct option is B.

5 0

3 years ago

Calculate the energy required to ionize a hydrogen atom to an excited state where the electron is initially in the n = 5 energy

SVETLANKA909090 [29]

. The energy of shells in a hydrogen atom is calculated by the formula E = -Eo/n^2 where n is any integer, and Eo = 2.179X10^-18 J. So, the energy of a ground state electron in hydrogen is:

E = -2.179X10^-18 J / 1^2 = -2.179X10^-21 kJ

Consequently, to ionize this electron would require the input of 2.179X10^-21 kJ

2. The wavelength of a photon with this energy would be:

Energy = hc/wavelength

wavelength = hc/energy

wavelength = 6.626X10^-34 Js (2.998X10^8 m/s) / 2.179X10^-18 J = 9.116X10^-8 m

Converting to nanometers gives: 91.16 nm

3. Repeat the calculation in 1, but using n=5.

4. Repeat the calculation in 2 using the energy calculated in 3.

7 0

3 years ago

Read 2 more answers