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Oxana [17]
3 years ago
5

Calculate the concentration in molality of calcium phosphate in a solution containing 250.0 grams of pure water when the freezin

g point is -8.5 C
Chemistry
1 answer:
NARA [144]3 years ago
4 0
The function:
f ( x ) = x * 0.965^t
where x is the initial amount and t is the number of the years
80 = x * 0.965^3
80 = x  *  0.89632
x = 80 : 0.89632 ≈ 89
Answer:
The initial amount of animals was <span>89.</span>
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Calculate the hydroxide ion consentration of a solution with pH = 3.25. show all calculations leading to your answer.
lidiya [134]
First you calculate the pOH of the solution:

pH+ pOH = 14

3.25 + pOH = 14

pOH = 14 - 3.25

pOH = 10.75

<span>Concentration of [OH]</span>⁻<span> in solution:
</span>
[ OH⁻ ] = 10 ^{-pOH}

[ OH⁻ ]  = 10^ - 10.75

[OH⁻] = 1.778 x 10⁻¹¹ M

hope this helps !


6 0
3 years ago
How many moles of hydrogen ions are formed in the ionization of 0.250 moles of H2SO4?
True [87]

Answer:

The ionization of 0.250 moles of H₂SO₄ will produce 0.5 moles of H⁺ (hydrogen ion)

Explanation:

From the ionization of H₂SO₄, we have

H₂SO₄ → 2H⁺ + SO₄²⁻

Hence, at 100% yield, one mole of H₂SO₄ produces two moles of H⁺ (hydrogen ion) and one mole of SO₄²⁻ (sulphate ion), therefore, 0.250 moles of H₂SO₄ will produce 2×0.250 moles of H⁺ (hydrogen ion) or 0.5 moles of H⁺ (hydrogen ion) and 0.25 moles of SO₄²⁻ (sulphate ion).

That is; 0.250·H₂SO₄ → 0.5·H⁺ + 0.250·SO₄²⁻.

4 0
3 years ago
Which of the following most accurately describes a regulatory molecule that must be transported to its place of action within th
Sonbull [250]

Answer:

the answer is hormone

Explanation:

because it is

5 0
2 years ago
In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is.
Travka [436]
<h2><u>Question :-</u></h2>

In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is.

a) Reduced, and the oxidation number changes from +1 to 0.

b) Reduces and the oxidation number changes from +2 to 0.

c) Oxidized and the oxidation number changes from 0 to +1.

d) Oxidized, and the oxidation number changes from +1 to 0.

<h3>____________________</h3>

<h2><u>Solution :-</u></h2>

<h3><u>Given Information :-</u></h3>

  • <u>Reaction ➢</u> Pb + 2Ag⁺ ⟶ Pb²⁺ + 2Ag

<h3><u>To Find :-</u></h3>

  • Whether Ag⁺ is:-

  • a) Reduced, and the oxidation number changes from +1 to 0.

  • b) Reduces and the oxidation number changes from +2 to 0.

  • c) Oxidized and the oxidation number changes from 0 to +1.

  • d) Oxidized, and the oxidation number changes from +1 to 0.

<h3><u>Answer :-</u></h3>

Firstly let us know the meaning of Oxidation & Reduction and Oxidizing & Reducing Agent :-

  1. Oxidation is process of loss of electron(s). Either atom or ion undergoing oxidation, is known as reducing agent.
  2. Reduction is process of gain of electron(s). Either atom or ion undergoing reduction, is known as oxidizing agent.

In this reaction, Ag⁺ gains an electron to get <u>reduced</u> to Ag. The oxidation number changes from +1 to 0. Therefore, Ag+ is an oxidizing agent.

Since, this possibility is given in option a). Reduced, and the oxidation number changes from +1 to 0. Hence, option a is the correct answer.

<h3>____________________</h3>

<h2><u>Final Answer :-</u></h2>

  • Option a. Reduced, and the oxidation number changes from +1 to 0 is correct answer.

<h3>____________________</h3>
5 0
2 years ago
How many valence electrons are transferred from the calcium atom to iodine in the formation of the compound calcium iodide?
Andreas93 [3]

Answer:

Two electrons.

Explanation:

Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or 1s^22s^22p^63s^23p^64s^2

There are 2 valence electrons of Calcium.

Iodine is the element of seventeenth group and fifth period. The electronic configuration of Iodine is - 2, 8, 18, 18, 7 or [Kr]4d^{10}5s^25p^5

There are 7 valence electrons of iodine.

Calcium iodide, CaI_2 is formed when 2 valence electrons of calcium are loosed and they are gained by 2 atoms of iodine.

7 0
3 years ago
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