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3 years ago

Solutions and colloids which contain similarly sized particles can be effectively separated using paper filtration.

Chemistry

2 answers:

mojhsa [17]3 years ago

6 0

False cause there particles arent large enough to be filtered

oee [108]3 years ago

4 0

Answer:

The given statement is false.

Explanation:

A solution is defined as the solution in which the components gets completely dissolved in it. Particles are evenly spread in these solutions. These solution does not scatter light falling on it.

A colloid is defined as the mixtures when physical boundary is seen between the dispersed phase and dispersed medium. They scatter the light falling on it.

Particle size of solutions are smaller than that of the colloids.But size of colloids particles is smaller than the size of pores filter paper used in filtration process due to which they easily escape through filter and results in no separation.

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In the chemical reaction:

tiny-mole [99]

Answer:

Explanation:

6 0

2 years ago

A sample of a substance has a mass of 4.2 grams and a volume of 6 milliliters. The density of this substance is

Tanzania [10]

Hello!

Mass =4.2 g

Volume =6 mL

Therefore:

Density = mass / volume

Density = 4.2 / 6

Density = 0.7 g/mL

Hope that helps!

4 0

3 years ago

Read 2 more answers

What is the total energy change for the following reaction:CO+H2O-CO2+H2

Alekssandra [29.7K]

Answer:

$\large \boxed{\text{-41.2 kJ/mol}}$

Explanation:

Balanced equation: CO(g) + H₂O(g) ⟶ CO₂(g) + H₂(g)

We can calculate the enthalpy change of a reaction by using the enthalpies of formation of reactants and products

$\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)$

(a) Enthalpies of formation of reactants and products

$\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{CO(g)} & -110.5 \\\text{H$_{2}$O} & -241.8\\\text{CO$_{2}$(g)} & -393.5 \\\text{H$_{2}$(g)} & 0 \\\end{array}$

(b) Total enthalpies of reactants and products

$\begin{array}{ccr}\textbf{Substance} & \textbf{Contribution)/(kJ/mol})&\textbf{Sum} \\\text{CO(g)} & -110.5& -110.5 \\\text{H$_{2}$O(g)} &-241.8& -241.8\\\textbf{Total}&\textbf{for reactants} &\mathbf{ -352.3}\\&&\\\text{CO}_{2}(g) & -393.5&-393.5 \\\text{H}_{2} & 0 & 0\\\textbf{Total}&\textbf{for products} & \mathbf{-393.5}\end{array}$

(c) Enthalpy of reaction $\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)= \text{-393.5 kJ/mol - (-352.3 kJ/mol}\\= \text{-393.5 kJ/mol + 352.3 kJ/mol} = \textbf{-41.2 kJ/mol}\\ \text{The total enthalpy change is $\large \boxed{\textbf{-41.2 kJ/mol}}$}$

4 0

3 years ago

Is anyone online 2 help,Sodium is a reactive metal.Why nd don't spam brainlest and thx is waiting answer it ❤️

morpeh [17]

It is because sodium is one of the most reactive metals.

There is a reaction would take place between magnesium and sodium chloride.

The chemical reaction between these two metals is given below.

It is Mg + 2NaCl >> MgCl2. + 2Na.

The symbol of this chemical element is Na.

It has the atomic number of eleven

Hope this helps *smiles*

6 0

3 years ago

2+4 help please i will fail 6th grade

andrey2020 [161]

Answer:

Explanation:

lol

4 0

2 years ago