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3 years ago

Select all that apply.

2 answers:

7 0

Burning a cake, burning firewood, and leaf color from summer to fall.

Chemical changes are changes in the composition of a substance resulting from a chemical reaction

It changes from one substance into a new substance.

Shredding paper is a physical change because the paper is still paper. Even if you cut it, you are not changing the chemical composition of it.

MariettaO [177]3 years ago

6 0

I think leaf color from summer to fall

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You are looking at two samples of iron. One sample is very small and came from the red soil on the planet Mars. The other sample

aivan3 [116]

The two samples don’t contain different atoms so it will be false

3 0

3 years ago

Help idk if I got the right answer A D B C E

olganol [36]

Answer:

Explanation:

3 0

4 years ago

A chemist observed bubbling and fizzing after adding an acid solution to a

Lisa [10]

Answer:

a chemical reaction occured

Explanation:

bubbling and fizzing after adding a substance, most offten means a chemical reaction is happening

7 0

3 years ago

5. What are the relative rates of diffusion for methane, CH, and oxygen, O2? If O2 la travels 1.00 m in a certain amount of time

11Alexandr11 [23.1K]

Answer:

The relative rates of diffusion for methane and oxygen is 1.4142.

Methane gas will be able to travel 1.4142 meter in the same conditions.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. Mathematically written as:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

We are given:

Molar mass of methane gas, m = 16 g/mol

Molar mass of oxygen gas,m' = 32 g/mol

By taking their ratio, we get:

$\frac{d_{CH_4}}{d_{O_2}}=\sqrt{\frac{m'}{m}}$

$\frac{d_{CH_4}}{d_{O_2}}=\sqrt{\frac{32}{16}}=1.4142$

The relative rates of diffusion for methane and oxygen is 1.4142.

If oxygen gas travels 1 meters in time t.

Rate of diffusion of oxygen = $d_{O_2}=\frac{1 m}{t}$

If methane gas travels travels in y meters in time t.

Rate of diffusion of methane= $d_{CH_4}=\frac{y }{t}$

$\frac{d_{CH_4}}{d_{O_2}}=\frac{\frac{y }{t}}{\frac{1 m}{t}}=1.4142$

y = 1.4142 m

Methane gas will be able to travel 1.4142 meter in the same conditions.

8 0

3 years ago

Select the correct answer from each drop-down menu.

Grace [21]

Answer:

An SCl2 molecule has polar bonds and a bent angular molecular shape. As a result, an SCl2 molecule is polar.

Explanation:

It is a covalent compound made up of angular molecules that contain two chlorine atoms attached to one sulfur atom. Sulfur undergoes sp3 hybridization and has two pairs of nonbonding electrons. Given their geometry and the difference in electronegativity between chlorine and sulfur, they are molecules with a marked polar character. The bond angle between the sulfur atom and the two chlorine atoms is 109.5°, since the two vectors are of equal intensity but their directions do not coincide; if they are added vectorially, they do not cancel each other out, making the molecule polar.

6 0

3 years ago