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natka813 [3]
3 years ago
14

Jack researched J.J. Thomson’s experiments. Read Jack’s summary below and find the error.

Chemistry
1 answer:
WINSTONCH [101]3 years ago
8 0

Answer:

D. Error is in sentence 1. The beam was a cathode ray.

Explanation:

Legit just looked up his experiments and it said right off the bat he studied cathode rays not gamma.

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Bakit mahalaga ang paghahanda ng pambansang badyet sa isang taon?​
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Explanation:

8 0
2 years ago
What volume of carbon dioxide, at 1 atm pressure and 112°C, will be produced when 80.0 grams of methane is burned?
Vadim26 [7]

Answer:

158 L.

Explanation:

What is given?

Pressure (P) = 1 atm.

Temperature (T) = 112 °C + 273 = 385 K.

Mass of methane CH4 (g) = 80.0 g.

Molar mass of methane CH4 = 16 g/mol.

R constant = 0.0821 L*atm/mol*K.

What do we need? Volume (V).

Step-by-step solution:

To solve this problem, we have to use ideal gas law: the ideal gas law is a single equation which relates the pressure, volume, temperature, and number of moles of an ideal gas. The formula is:

PV=nRT.

Where P is pressure, V is volume, n is the number of moles, R is the constant and T is temperature.

So, let's find the number of moles that are in 80.0 g of methane using its molar mass. This conversion is:

80.0g\text{ CH}_4\cdot\frac{1\text{ mol CH}_4}{16\text{ g CH}_4}=5\text{ moles CH}_4.

So, in this case, n=5.

Now, let's solve for 'V' and replace the given values in the ideal gas law equation:

V=\frac{nRT}{P}=\frac{5\text{ moles }\cdot0.0821\frac{L\cdot atm}{mol\cdot K}\cdot385K}{1\text{ atm}}=158.04\text{ L}\approx158\text{ L.}

The volume would be 158 L.

6 0
11 months ago
Would it be D....????<br> HELPPPPPP
AlekseyPX

Answer:

yes

Explanation:

6 0
3 years ago
2 . a) b) (1) List three oxides of nitrogen ( 3ks) State Charles law (2mks) (111) A given mass of gas occupies 300cm at 900mmHg
Travka [436]

ask correctly so that your points cant make fun of others

7 0
2 years ago
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