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dlinn [17]
3 years ago
6

PLEASE HELP it takes tsooo long! lol ima fail! please help! thanks!

Physics
1 answer:
svetoff [14.1K]3 years ago
5 0

Answer:

Mechanical

Explanation:

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How are energy, force, and the motion of objects related?
OLEGan [10]

Answer:

When two objects interact, each one exerts a force on the other that can cause energy to be transferred to or from the object. For example, when energy is transferred to an Earth-object system as an object is raised, the gravitational field energy of the system increases. This energy is released as the object falls; the mechanism of this release is the gravitational force. Likewise, two magnetic and electrically charged objects interacting at a distance exert forces on each other that can transfer energy between the interacting objects.

Explanation:

Even when an object is sitting still, it has energy stored inside that can be turned into kinetic energy (motion). ... A force is a push or pull that causes an object to move, change direction, change speed, or stop. Without a force, an object that is moving will continue to move and an object at rest will remain at rest.

5 0
3 years ago
Read 2 more answers
A student weighing 700 N climbs at constant speed to the top of an 8 m vertical rope in 10 s. The average power expended by the
stich3 [128]

Answer:

3.    560W

Explanation:

First we calculate the work required for the 700N weigh student to climb up by 8 meters. Work is force times distance

W = Fs = 700 * 8 = 5600J

The average power is defined as the rate of energy expended over a unit of time. In order words, work divided by time duration

P = W/t = 5600 / 10 = 560 W

3 0
3 years ago
A) A real object 4.0 cm high stands 30.0 cm in front of a converging lens of focal length 23 cm. Find the image distance, the im
vfiekz [6]

Explanation:

Given that,

Height of object = 4.0 cm

Distance of the object u= -30.0 cm

Focal length = 23 cm

We need to calculate the image distance

Using lens's formula

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Where, u = object distance

v = image distance

f = focal length

Put the value into the formula

\dfrac{1}{v}-\dfrac{1}{-30}=\dfrac{1}{23}

\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{30}

\dfrac{1}{v}=\dfrac{7}{690}

v=98.57\ cm

We need to calculate the height of the image

Using formula of height

\dfrac{h'}{h}=\dfrac{-v}{u}

Where, h' = height of image

h = height of object

\dfrac{h'}{4}=\dfrac{-98.57}{-30}

h'=\dfrac{98.57\times4}{30}

h'=13.14\ cm

The image is real and inverted.

(b). Now, object distance u = 13.0 cm

We need to calculate the image distance

Using lens's formula

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{13.0}

\dfrac{1}{v}=-\dfrac{10}{299}

v=-29.9\ cm

We need to calculate the height of the image

\dfrac{h'}{4}=\dfrac{-(-29.9)}{-13.0}

h=-\dfrac{29.9\times4}{13.0}

h=-9.2\ cm

The image is virtual and erect.

Hence, This is required solution.

6 0
3 years ago
How do clouds become stars ?
kenny6666 [7]
Stars form inside relatively dense concenstrations of interstellar gas and dust known as molecular clouds.





hope it helps
3 0
3 years ago
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A machine has a mechanical advantage of 4.5. What force is put out by the machine if the force applied to the machine is 800 N?
Ghella [55]

If the machine's mechanical advantage is 4.5, that means that

Output force = (4.5) x (Input force) .

We know the input force, and we need to find the output force.  Rather than wander around the room looking at the floor while our hair smolders, let's try putting the numbers we know into the equation I wrote up there.  OK ?

Output force = (4.5) x (Input force)

Output force = (4.5) x (800 N)

Now dooda multiplication:

<em>Output force = 3,600 N</em> .  

That's exactly what the question asked for.  So we're done !

3 0
3 years ago
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