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goldenfox [79]
3 years ago
7

in a sample of 80 adults, 25 said that they would buy a car from a friend. three adults are selected at random without replaceme

nt. find the probability that none of the three would buy a car from a friend.
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
5 0

Answer:

31.9%

Step-by-step explanation:

We have that,

Total number of adults = 80

Number of people that would buy a car from a friend = 25

So, the number of people that would not buy a car from a friend = 80-25 = 55.

Since, three people are selected randomly.

Thus, the probability that none of them would buy a car from a friend is given by,

\frac{\binom{55}{3}}{\binom{80}{3}}

i.e. \frac{\frac{55!}{3!\times 52!}}{\frac{80!}{3!\times 77!}}

i.e. \frac{55!\times 3!\times 77!}{3!\times 52!\times 80!}

i.e. \frac{55\times 54\times 53}{80\times 79\times 78}

i.e. \frac{157410}{492960}

i.e. 0.319

Thus, the probability of people who would not buy a car from a friend is 0.319 i.e. 31.9%

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erma4kov [3.2K]

Answer:

\frac{n_p}{n_s}=\frac{1}{1000}

Step-by-step explanation:

Given voltage of primary coil is V_p=12V

And voltage of secondary coil is V_s=12,000V

A transformer is a device that contains primary and secondary coil. These coils are mounted on soft iron. The change in voltage depends upon the number of turns of primary coil (n_p) and secondary coil (n_s).

Following equation represents the relation between them.

\frac{V_s}{V_p} =\frac{n_s}{n_p}\\\\\frac{12,000}{12}=\frac{n_s}{n_p}\\\\1000=\frac{n_s}{n_p}

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5 0
3 years ago
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sergey [27]

           - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond

         Write an equation for the line that passes through (0, 1) and has a slope of 2 (in point-slope form).

\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond

<u>Point-slope form</u>:-

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Substitute 1 for y₁, 2 for m, and 0 for x₁:-

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So we conclude that Option B is correct.

<h3>Good luck.</h3>

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