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loris [4]
3 years ago
7

Which of the following is a step in the conversion of 2.5 hm3 to L?

Chemistry
1 answer:
BARSIC [14]3 years ago
4 0
To convert to L
2.5 hm^3 * (100m/hm)^3 *1000 L/m^3 gives a volume of 2.5*10^9 L
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3mL of cyclohexanol (density = 0.9624 g/mL, Molecular weight = 100.158 g/mol) reacts with excess sulfuric acid to produce cycloh
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Answer:

n_{C_6H_{10}}=0.03molC_6H_{10}

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:

n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}

Besides, the mass could be computed as well by using the molar mass of cyclohexene:

m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}

Even thought, the volume could be also computed by using its density:

V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}

Best regards.

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3 years ago
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