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tatyana61 [14]
3 years ago
13

Use the following image to complete the matching exercise below. You will match the number from each white box in the image with

the proper term. (Note: there is nothing to submit in the text box below the image).
Chemistry
1 answer:
Marat540 [252]3 years ago
7 0
Can you describe the image
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Use the pie section above to answer this question.
Vinvika [58]

Answer:

can you show me a picture of the pie chart?

Explanation:

if i dont see the pie chart then this question isn't possible to answer

8 0
3 years ago
PLEASE HELP AS SOON AS POSSIBLE
lakkis [162]
1. Atoms
2 neutral, proton
3.
7 0
3 years ago
How is phosphorylation of glyceraldehyde 3-phosphate in the payment phase of glycolysis different from phosphorylation of glucos
svet-max [94.6K]

In the preparatory phase of glycolysis, two molecules of ATP are invested and the hexose chain is cleaved into two triose phosphates. During this, the phosphorylation of glucose and its conversion to glyceraldehyde-3-phosphate take place.  During this phase, the conversion of glyceraldehyde-3-phosphate to pyruvate and the coupled formation of ATP take place. Because Glucose is split to yield two molecules of D-Glyceraldehyde-3-phosphate, each step in the payoff phase occurs twice per molecule of glucose.

Glyceraldehyde 3-phosphate dehydrogenase Simultaneous oxidation and phosphorylation of G3P produce 1,3-bisphosphoglycerate (1,3-BPG) and nicotine adenine dinucleotide (NADH).

The divalent cation also affected the response of the enzyme from the endosperm and shoots to adenine nucleotides and inorganic pyrophosphate.

This phase is also called the glucose activation phase. In the preparatory phase of glycolysis, two molecules of ATP are invested and the hexose chain is cleaved into two triose phosphates. During this, the phosphorylation of glucose and its conversion to glyceraldehyde-3-phosphate take place. Steps 1, 2, 3, 4, and 5 together are called the preparatory phase.

For more information on phosphorylation click on the link below:

brainly.com/question/7465103

#SPJ4

7 0
1 year ago
If 0.583 g of ammonia (NH3) is dissolved to make 250 mL of solution, what is the molarity?
Misha Larkins [42]

Answer:

0.137 M NH3

Explanation:

First divide the mass of NH3 by the molar mass of NH3, and then divide by the volume to get molarity.

0.583 g / 17.031 g/mol = 0.0342 mol NH3

0.0342 mol NH3 / 0.250 L = 0.137 M NH3

7 0
3 years ago
F.ree points for all!
shepuryov [24]

Answer:

here...I helped u! XD

jkjk...I'll got to the other questions too...dw! XD

Explanation:

4 0
3 years ago
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