Question

The pressure of an ideal gas is doubled during a process in which the energy given up as heat by the gas equals the work done on the gas. As a result, the volume is : (A) doubled (B) halved (C) unchanged

Answer 1

Answer:

$V' = \frac{V}{2}$

So volume is halved

Explanation:

As we know that heat energy given to the gas is equal to the work done

so as per first law of thermodynamics we know that

$\Delta Q = W + \Delta U$

now we know that

$\Delta Q = W$

so we have

$\Delta U = 0$

so we have temperature of the gas is constant

so it is an isothermal process

so here we can say

$PV = constant$

so here we can say

$P(V) = (2P)V'$

so we have

$V' = \frac{V}{2}$