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Vanyuwa [196]
3 years ago
14

Someone plzzz helpppppp with this last question

Physics
1 answer:
vredina [299]3 years ago
7 0

Answer:

I dont know someone deleted answers. But they were wrong. INERTIA IS CORRECT I DID THIS IN MY SCHOOL

C IS CORRECT

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A package is dropped from an airplane flying at an altitude of 69.2 m with a velocity of 1.40 x 10^2 km/h. Calculate the horizon
Andrew [12]
69.2 m with a velocity of 1.40* 10^2 km/h.

5 0
3 years ago
If gas costs $3.65 per gallon at a local service station, how many cubic feet of gas can a customer buy with $40 ?
svet-max [94.6K]
Hi, thank you for posting your question here at Brainly. 

For consistency you must convert gallons to cubic foot. The conversions are:

7.481 gal = 1 ft3

Then, $3.65 per gallon becomes $27.3 per ft3. If you buy $40 worth of gas, you get $40/$27.3 = 1.46 ft3 of gas. 

If you can travel for 4 miles per ft3, then with the amount of gas you have, you can travel up to 5.85 miles.

(4 miles/ft3)*(1.46 ft3) = 5.85 miles
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3 years ago
Determine the potential difference between two charged parallel plates that are 0.50 cm apart and have an electric field strengt
jeka57 [31]
If the field strength between the plates is 9 volts per cm, then over a path of 1/2cm parallel to the field, the potential changes by (1/2) x (9 volts) = 4.5 volts.
5 0
3 years ago
Read 2 more answers
What is the frequency of a wave with a speed of 45 m/s and a wavelength of 2.5 m
mart [117]

Answer:

.05

Explanation:

wavelength/frequency = wave speed

45 = 2.5/x

x = 0.05

5 0
3 years ago
Based on the simple blackbody radiation model described in class, answer the following question. The planets Mars and Venus have
Lera25 [3.4K]

Answer:

The extent of greenhouse effect on mars is G_m =  87 K  

Explanation:

From the question we are told that

     The albedo value of Mars is  A_1  = 0.15

      The albedo value of Mars is  A_2  = 0.15

       The surface temperature of Mars is  T_1 = 220 K

        The surface temperature of Venus is  T_2 = 700 K

          The distance of Mars from the sun is d_m = 2.28*10^8 \ km = 2.28*10^8* 1000 = 2.28*10^{11} \  m

          The distance of Venus from sun is  d_v = 1.08 *10^{8} \ km = 1.08 *10^{8} * 1000 =  1.08 *10^{11} \ m

       The radius of the sun is R = 7*10^{8} \ m

        The energy flux is   E = 6.28 * 10^{7} W/m^2

The solar constant for Mars is mathematically represented as

 

          T = [\frac{E R^2 (1- A_1)}{\sigma d_m} ]

Where \sigma is the Stefan's constant with a value  \sigma = 5.6*10^{-8} \ Wm^{-2} K^{-4}

So substituting values

         T = \frac{6.28 *10^{7} * (7*10^8)^2 * (1-0.15)}{(5.67 *10^{-8}) * (2.28 *10^{11})^2)}

          T = 307K

So the greenhouse effect on Mars is  

           G_m =  T -  T_1

           G_m =  307 - 220

          G_m =  87 K

   

3 0
4 years ago
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