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Ksivusya [100]
3 years ago
15

How much heat is required to change 25.0 g of water from solid to liquid at 0 oC? Water: ΔHfus = 334 J/g; ΔHvap= 2260J/g

Chemistry
1 answer:
xxMikexx [17]3 years ago
3 0

Answer:

The heat required to change 25.0 g of water from solid ice to liquid water at 0°C  is 8350 J

Explanation:

The parameters given are

The temperature of the solid water = 0°C

The heat of fusion,   = 334 J/g

The heat of vaporization, = 2260 J/g

Mass of the solid water = 25.0 g

We note that the heat required to change a solid to a liquid is the heat of fusion, from which we have the formula for heat fusion is given as follows;

ΔH =  m ×

Therefore, we have;

ΔH =  25 g × 334 J/g = 8350 J

Which gives the heat required to change 25.0 g of water from solid ice to liquid water at 0°C  as 8350 J.

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Why do we use 51.0mL of NaOH but only 50.0mL of HCl?
bixtya [17]

Answer

Na OH reacts with H Cl and forms Na Cl and H₂O

NaOH + HCl   →   NaCl + H₂O                                              

Here we can see that  1 mole of NaOH reacting with 1 mole of HCl and forming 1 mole of NaCl and 1 mole of H₂O

when  NaOH and HCl are added together in equal amount then they will completely neutralize each other but NaOH is hygroscopic in nature which means it can absorb water from air so it will not be weighted accurately.

hence, for neutralization we will take extra NaOH.

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3 years ago
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Arte-miy333 [17]

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Explanation:

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2 years ago
The natural tendence of an object to resist change in its state of motion is:
melisa1 [442]

Inertia. Inertia is the natural tendency of bodies to remain in their states of either rectilinear or resting motion.

5 0
2 years ago
Is there law of conversation of Volume? If two different liquids say you take 100ml of liquid A and 100 ml of liquid B and mix t
victus00 [196]

Answer:

200 mL

Explanation:

You simply add the volumes :) If this was a case that involved titration, you would use the formula M1V1 = M2V2. I do not know if that is what you were referring to but based on the information you gave, you simply add the two volumes.

4 0
3 years ago
When dipentyl ether is treated with HI, what type of reaction occurs? both SN1 and SN2 SN2 E1 SN1 E2
masha68 [24]

Answer:

SN2

Explanation:

The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.

The second step of the reaction may proceed by either SN1 or SN2 mechanism depending on the structure of the ether. Methyl and primary ethers react with HI by SN2 mechanism while tertiary ethers react with HI by SN1 mechanism. Secondary ethers react with HI by a mixture of both mechanisms.

Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.

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