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tiny-mole [99]
3 years ago
7

Calculate the kinetic energy in joules of a 10 g bullet moving at 300 m/s.

Physics
1 answer:
Tomtit [17]3 years ago
3 0

Answer:450joules

Explanation:

Let mass=m velocity =v

Mass given=10g=(10/1000)kg=0.01kg

Velocity given =300m/s

Kinetic energy =(m x v^2)/2

Kinetic energy =(0.01x300^2)/2

Kinetic energy =(0.01 x 90000)/2

Kinetic energy =900/2

Kinetic energy =450joules

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What kind of lens is there in our eyes? where does it form the image of an object?​
Goshia [24]

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What hidden costs of using DDT did Rachel Carson call attention to?
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3 years ago
Find the magnitude of the sum
shusha [124]

Answer:

\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m

Explanation:

<u>Sum of Vectors in the Plane</u>

Given two vectors

\displaystyle \vec{v_1}\ ,\ \vec{v_2}

They can be expressed in their rectangular components as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_2}=

The sum of both vectors can be done by adding individually its components

\displaystyle \vec{v_1}+\vec{v_2}=

If the vectors are given as a magnitude and an angle (M\ ,\ \theta ), each component can be found as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_2}=

The first vector has a magnitude of 3.14 m and an angle of 30°, so

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=

The second vector has a magnitude of 2.71 m and an angle of -60°, so

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=

The sum of the vectors is

\displaystyle \vec{v_1}+\vec{v_2}=

\displaystyle \vec{v_1}-\vec{v_2}=

Finally, we compute the magnitude of the sum

\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{(4.08)^2+(-0.78)^2}

\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{17.25}

\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m

3 0
3 years ago
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