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PolarNik [594]
4 years ago
15

According to the nfpa, the upper human survivability limit is approximately:

Physics
1 answer:
wolverine [178]4 years ago
5 0

The National Fire Protection Association (NFPA) states that the furthest reaches of human temperature viability is 212°F, well beneath temperatures found in most noteworthy structure fires that are past the development (early) stage. In the present fire conditions, temperatures higher than 500°F can be effortlessly gotten inside three to four minutes. Flashover, which happens at roughly 1,100°F, can grow well under five minutes.2 If a space isn't legitimate for firefighters, caught casualties aren't probably going to survive either. Set aside the opportunity to make it safe and keep your firefighters from going for broke.

 

<span>60% of the casualties were found to have been presented to warm (most at temperatures over 200°F; some were beneath) and mugginess for six to seven minutes (remote from the fire range).</span>

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Complete each sentence with the correct type of lens.
andrey2020 [161]

Answer:

Convex and Concave

Explanation:

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6 0
3 years ago
You prepare tea with 0.250 kg of water at 85.0 ºC and let it cool down to room temperature (20.0 ºC) before drinking it. Essenti
vladimir2022 [97]

Answer:

232 J/K

Explanation:

The amount of heat gained by the air = the amount of heat lost by the tea.

q_air = -q_tea

q = -mCΔT

q = -(0.250 kg) (4184 J/kg/ºC) (20.0ºC − 85.0ºC)

q = 68,000 J

The change in entropy is:

dS = dQ/T

Since the room temperature is constant (isothermal):

ΔS = ΔQ/T

Plug in values (remember to use absolute temperature):

ΔS = (68,000 J) / (293 K)

ΔS = 232 J/K

5 0
3 years ago
What force causes a 1-kg mass to accelerate at a rate of 1 meter per second each second?
Zigmanuir [339]

Answer:

F=1N

Explanation:

Conceptual analysis

To solve this problem we apply Newton's second law:

The acceleration of an object is proportional to the force F acting on it and inversely proportional to its mass m.

a = F / m

Where,

F = m * a Formula (1)

F: Force in Newtons (N)

m: mass in kg

a: acceleration in m/(s^2)

a = v / t  Formula (2)

v: speed in m/s

t: time in seconds (s)

Known information

We know the following data:

m = 1kg

v = 1 m/s

t = 1s

Development of the problem:

In the Formula (2): a = \frac{\frac{1m}{s}}{1s} = 1 \frac{m}{s^2}

In the Formula (1): F=1kg* 1 \frac{m}{s^2}=1N

8 0
3 years ago
For the first 10 seconds a squirrel runs 3 m/s to look for an acorn. The next 5 seconds he eats an acorn that he finds. Afterwar
Gala2k [10]

Distance covered by the squirrel to look for an acorn :

d = ( 3 m/s ) × 10 s = 30 m.

Time taken to eat an Acron is 5 seconds.

Time taken to cover distance of 30 m with 2 m/s speed is :

T=\dfrac{30}{2}\ s= 15 \ s

Therefore, total time take to  get back to where he started is ( 10+5+15 ) = 30 s.

Hence, this is the required solution.

7 0
3 years ago
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Scorpion4ik [409]

Answer:

<h3>C. </h3>

Explanation:

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