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2 years ago

All redox reactions are combustion reactions. True or False?

Chemistry

1 answer:

VladimirAG [237]2 years ago

8 0

Answer:

the answer is false

Explanation:

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In the figure below, two nonpolar molecules are interacting.Which interaction would most likely cause these molecules to repel e

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Two non-polar molecules are most likely to interact by
induced dipole-induced dipole interaction.

Non-polar substances do not have a permanently established charge distribution due to similar electron affinities of the atoms that are present. Moreover, due to the absence of a polar hydrogen, they cannot exhibit hydrogen bonding. They interact with one another by induced dipole-induced dipole interactions which arise from the molecules of the substances coming into close vicinity of one another.

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3 years ago

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Why is it important to offer evidence to support statements about experiments?

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3 years ago

In an experiment, students were given an unknown mineral. The unknown mineral was placed in 150 ml of water. Once in the water,

Dahasolnce [82]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

But from the question

volume = final volume of water - initial volume of water

volume = 165 - 150 = 15 mL

We have

$density = \frac{225}{15} = 15 \\$

We have the final answer as

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2 years ago

Chemistry and physics are so closely related that sometimes the fields overlap. Which of the following experiments might both ch

andrew11 [14]

What are the choices?

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3 years ago

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What volume of CH4(g), measured at 25oC and 745 Torr, must be burned in excess oxygen to release 1.00 x 106 kJ of heat to the su

anastassius [24]

Answer:

$V=27992L=28.00m^3$

Explanation:

Hello,

In this case, the combustion of methane is shown below:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

And has a heat of combustion of −890.8 kJ/mol, for which the burnt moles are:

$n_{CH_4}=\frac{-1.00x10^6kJ}{-890.8kJ/mol}= 1122.6molCH_4$

Whereas is consider the total released heat to the surroundings (negative as it is exiting heat) and the aforementioned heat of combustion. Then, by using the ideal gas equation, we are able to compute the volume at 25 °C (298K) and 745 torr (0.98 atm) that must be measured:

$PV=nRT\\\\V=\frac{nRT}{P}=\frac{1122.6mol*0.082\frac{atm*L}{mol*K}*298K}{0.98atm}\\\\V=27992L=28.00m^3$

Best regards.

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3 years ago