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3 years ago

How does a green leaf appear in red light? Use what you know about reflection and absorption of light.

Physics

2 answers:

Scilla [17]3 years ago

6 0

I think the answer is Black. Hope this helps

skelet666 [1.2K]3 years ago

4 0

Answer: 1.black

Explanation:

A green object, like the leaf in this problem, absorbs all colors of light except for the green color. In fact, the object is able to reflect only the green light, and this is why the object appears green to us: because this is the only color reflected by the leaf.

Therefore, if we hit the leaf with red color, it will appear black: in fact, the leaf is will absorb the red light, and there are no more colors to be reflected - therefore, the leaf will appear black (which corresponds to absence of color).

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3 years ago

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You have an incident ray from a medium with a n1=1, through a medium with a n2 =3.325. If the incident angle is equal to 0.478 r

sesenic [268]

Answer:

0.139 rad

Explanation:

We use Snell's law $n_1sin\theta_1=n_2sin\theta_2$ , where if $n_1$ is the refractive index of the medium containing the incident ray, $\theta_1$ would be the incident angle, and if $n_2$ is the refractive index of the medium containing the refracted ray, $\theta_2$ would be the refraction angle, which we want, so we do:

$sin\theta_2=\frac{n_1}{n_2}sin\theta_1$

And finally:

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We then insert our values:

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6 0

3 years ago

A car travels around a level, circular track that is 750m across. What coefficient of friction is required to ensure the car can

Crank

The coefficient of friction must be 0.196

Explanation:

For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:

$\mu mg = m\frac{v^2}{r}$

where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:

$\mu$ is the coefficient of friction between the tires and the road

m is the mass of the car

$g=9.8 m/s^2$ is the acceleration of gravity

v is the speed of the car

r is the radius of the curve

In this problem,

r = 750 m is the radius

$v=85 mph \cdot \frac{1609}{3600}=38.0 m/s$ is the speed

And solving for $\mu$ , we find the coefficient of friction required to keep the car in circular motion:

$\mu = \frac{v^2}{rg}=\frac{38.0^2}{(750)(9.8)}=0.196$

Learn more about circular motion:

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brainly.com/question/6372960

#LearnwithBrainly

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3 years ago

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Answer:

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2 years ago

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Answer:

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