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12345 [234]
3 years ago
7

Refractive index of water is 1.3. calculate the speed of light in water.​

Physics
2 answers:
wolverine [178]3 years ago
5 0

Answer:

The speed of light is faster in water. The Refractive index of water is 1.3 and the refractive index of glass is 1.5. From the equation n = c/v, we know that the refractive index of a medium is inversely proportional to the velocity of light in that medium. Hence, light travels faster in water.

Korolek [52]3 years ago
4 0

Answer:

2.31*10^{8} m/s

Explanation:

Employ the formula attached below,

n = c/v

1.3 = (3.0*10^8)/ x

(solve for x)

x= (3.0*10^8) / 1.3

x= 2.31*10^{8} m/s

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How would you define physics class in your own words ?
Andrei [34K]

Answer:

honestly i dont like physics class but for you im gonna write somethin' good but for me tho its B O R I N G

Explanation:

<em>Physics is the branch of science that deals with the structure of matter and how the fundamental constituents of the universe interact. It studies objects ranging from the very small using quantum mechanics to the entire universe using general relativity.</em>

3 0
3 years ago
What is the mechanical advantage of a 8 m ramp that rises 2 m to a stage?
Neko [114]

Answer:

Mechanical advantage = 4

Explanation:

Given the following data;

Distance of effort, de = 8m

Distance of ramp, dr = 2m

To find the mechanical advantage;

Mechanical advantage = de/dr

Substituting into the equation, we have;

Mechanical advantage = 8/2

Mechanical advantage = 4

5 0
3 years ago
A proton initially at rest is accelerated by a uniform electric field. The proton moves 5.62 cm in 1.15 x 10^-6 s. Find the volt
krok68 [10]

Answer:

49.85 V

Explanation:

u = 0, s = 5.62 cm, t = 1.15 x 10^-6 s

Let the electric field is E and voltage is V.

Use second equation of motion

s = ut + 1/2 a t^2

5.62 x 10^-2 = 0 + 0.5 a x (1.15 x 10^-6)^2

a = 8.5 x 10^10 m/s^2

m x a = q x E

E = m x a / q

E = (1.67 x 10^-27 x 8.5 x 10^10) / (1.6 x 10^-19)

E = 887.19 V/m

V = E x s

V = 887.19 x 5.62 x 10^-2 = 49.85 V

4 0
4 years ago
Un cuerpo de 3,5 kg se encuentra en reposo sobre un plano inclinado 37o. Está sujeto al extremo superior del plano inclinado med
Tems11 [23]

Answer:

1,1 m

Explanation:

Dado que;

coeficiente de fricción = 0,6

sabemos que W = R = mgcos 37 = 3.5Kg * 10m / s ^ 2 * cos37 = 27.95 N

coeficiente de fricción = fuerza / reacción normal (R)

Fuerza = 0.6 * 27.95 N

Fuerza (F) = 16.77 N

Recuerda que F = Ke

dónde;

K = constante de fuerza (15N / m)

e = extensión (lo desconocido)

e = F / K

e = 16,77 N / 15 N / m

e = 1,1 m

8 0
3 years ago
Which phrase best describes the path of a light wave
Reptile [31]

Answer:

C

Explanation:

Straight away from the source

7 0
3 years ago
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