Personally i would consider how many calories there are and how long it would take to burn that
Answer:
The net force exerted by the two charges is 10.97 x 10⁻⁵ N along negative x-direction.
Explanation:
K=1/4πϵ0, where ϵ0=8.854×10−12C2
K = 9x10⁹
The electric force on point charge q₃ due to charge q₂ is
F₃₂ = kq₃q₂ / (1.245)²
= (9x10⁹ * 49.5x10⁻⁹ * 30.5x10⁻⁹) / (1.245)²
= 13,587.75 x 10⁻⁹ / 1.55
= 8.76629 x 10⁻⁵ N
The electric force on point charge q₃ due to charge q₁ is
F₃₁ = kq₃q₁ / (1.695 - 1.245)²
= (9x10⁹ * 49.5x10⁻⁹ * 10.0x10⁻⁹) / 0.2025
= 2.2000 x 10⁻⁵ N
The net electric force on point charge q₃ is
F₃ = -F₃₁ - F₃₂
= - 8.76629 x 10⁻⁵ N - 2.2000 x 10⁻⁵ N
= 10.97 x 10⁻⁵ N along negative x-direction
Answer: E) Acceleration, net force
Explanation: In order to explain this problem we have to consirer that the uniform circulat motion has constant angular velocity (ω) and the vector velocity is changed its direction for any point that cover the circle but its modulus is contant and its value is v=ω*R. In order to ensure these conditions, the net force also the accelaration called centripetal must point to the center of the circular trajectory.