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Ymorist [56]
3 years ago
13

Which gas sample at STP has the same number

Chemistry
1 answer:
Flauer [41]3 years ago
8 0

<span>STP signifies standard temperature and pressure. This conditions are at 1 atmospheric pressure and 0 degrees Celsius. It has been said that at these conditions, one mole of a gas molecule is equivalent to 22.4 liters of volume. Therefore, the correct answer is the second option which is 2 L of CH4.</span>

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Sound waves, I'm pretty sure.
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A substance that does not conduct electricity as a solid but does conduct electricity when melted is most likely classified as
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Ionic compunds are able to conduct electricity when molten/in solution, but not when they are solid
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Read 2 more answers
LiOH + KCI → LiCl + KOH
yulyashka [42]

Answer:

35.42g

Explanation:

LiOH + KCI → LiCl + KOH

Let us determine the molar mass of LiOH and LiCl. This is illustrated below:

Molar Mass of LiOH = 7 + 16 + 1 = 24g/mol

Molar Mass of LiCl = 7 + 35.5 = 42.5g/mol.

Now, we can obtain the theoretical yield of LiCl as follow:

From the equation above,

24g of LiOH reacted to produce 42.5g of LiCl.

Therefore, 20g of LiOH will react to produce = (20 x 42.5)/24 = 35.42g of LiCl.

From the above calculations, the theoretical yield of LiCl is 35.42g

3 0
4 years ago
Between Lab Period 1 and Lab Period 2, design a separation scheme for all 4 cations. Use the results of your preliminary tests a
fiasKO [112]

Answer:

                    SEPARATION SCHEME FOR  CATIONS

GIVEN  CATIONS : Ag^{+} \ ,  Fe^{3+} , Cu^{2+}, Ni^{2+}

     

    Step 1:   Add 6mol/dm^3 of HCl to the mixture solution

    Result : This would cause a precipitate of AgCl to be formed

    Reaction :  Ag^{+} _{(aq)} + Cl^{-} _{(aq)}  ---------> AgCl(ppt)

    Step 2 : Next is to remove the precipitate and add H_2S to the remaining          

                 solution in the presence of 0.2 \ mol/dm^3 of HCl

     Result : This would cause a precipitate of CuS to be formed

     Reaction :  Cu^{2+}_{(aq)} + S^{2-}_{(aq)} ------> Cu_2S(ppt)

 

     Step 3: Next remove the precipitate then add 6 \ mol/dm^3 of aqueous      

                 NH_3 (NH_3 \cdot H_2 O) , process the solution in a centrifuge,when the  

                 process  is done then sort out the  precipitate from the  solution

                 Now this precipitate is   Fe(OH)_3 and the remaining solution

                contains  (Ni (NH_3)_6)

                 Next take out the precipitate to a different beaker and add HCl

                to it   this will dissolve it, then add a drop of NH_4SCN this will

                form  a precipitate  Fe(SCN)_{6}^{3-} which will have the color of

                 blood  indicating the presence of Fe^{3+}

             

   Reaction :   F^{3+}_{(aq)} + 30H^-_{(aq)} --------->Fe(OH)_3_{(aq)}

                        Fe (OH)_{(s)} _3  + 3H^{+}_{aq} -------> Fe^{3+}_{aq} + 3H_2O_{(l)}

                         Fe^{3+} + 6SCN^{-} -----> Fe(SCN)_6 ^{3-}

                      Now the remaining mixture contains Ni^{2+}

     

       

Explanation:

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A water molecule, because of its shape, is a polar molecule.
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