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3 years ago

Which of the following is NOT true about one mole?

1 answer:

7 0

The option in “the mass of 1me of carbon equals the mass of 1 mole of boron atoms” is false since

Mass=molesx molar mass

And the molar masses of these two elements are different so their masses aren’t equal

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Element X has the following valence electron configuration: [core]ns2np5. Element M has the following valence electron configura

alex41 [277]

Answer:

The kind of ionic compound formed is MX2.

Explanation:

Element X electron configuration is represented as [core] ns2np5. The group in the periodic table this element belong to is group 7A. The element group is called the halogen family. Element X cannot be stated specifically, because the number is represented with n. Element X will behave as an anions when it react with a metal(cations). Element X has a charge of -1. The element X will gain electron when it bond with a metal. Element X is a non metal . Elements in this group are fluorine, chlorine, bromine, iodine , astatine, and tennessine . The element X have 7 valency electrons.

Element M electronic configuration is represented as [core]ns2. The group in the periodic table this element belong to is group 2A . The element group is called the alkaline earth metals family . Element M will behave as a cation when it bond with a non metal. Element M is a metal , therefore it will likely lose electron to form cations during bonding . The charge of element M is 2+. Element M is positively charged. Elements that belong to this group includes beryllium, magnesium, calcium, strontium, barium and radium. Element M has 2 valency electrons.

The reaction between this 2 ions will likely form an ionic compound . The element M is the cations while the element X is the anions. The element M will lose 2 electron while 2 atoms of element X will gain 2 electrons.Element M will lose 2 electron to attain a stable configuration while 2 atoms of element X will gain a single electron each to attain a stable configuration.

M²+ and F- . This will form MX2 when you cross multiply the charge. The kind of ionic compound formed is MX2.

6 0

3 years ago

A galvanic cell consists of a Cu(s)|Cu2+(aq) half-cell and a Cd(s)|Cd2+(aq) half-cell connected by a salt bridge. Oxidation occu

Kryger [21]

Answer:

$Cd(s)|Cd^{2+}(aq) || Cu^{2+}(aq)|Cu(s)$

Explanation:

A galvanic cell is composed of two electrodes immersed in a suitable electrolyte and connected via a salt bridge. One of the electrodes serves as a cathode where reduction or gain of electrons takes place. The other half cell functions as an anode where oxidation or loss of electrons occurs.

The representation is given by writing the anode on left hand side followed by its ion with its molar concentration. It is followed by a salt bridge. Then the cathodic ion with its molar concentration is written and then the cathode.

As it is given that cadmium acts as anode, it must be on the left hand side and copper must be on right hand side.

$Cd(s)|Cd^{2+}(aq) || Cu^{2+}(aq)|Cu(s)$

6 0

4 years ago

PLZ HELP FAST

astra-53 [7]

#1
The correct answer is A.)

Because the animal has sperm that means that the offspring will be different. This is because at conception, the two parents sex cells combine their DNA to make a new creature.

#2
The correct answer is B.)

Genetic variation produces different offspring, and some are more adapted to others. The ones that survive pass on their genes. This is know as "Survival of the Fittest". Asexually organisms are exactly like their parents, so if they have any type of genetic defaults, then their offspring will get them too.

Hope this helps!

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3 0

3 years ago

The equilibrium constant for the formation of ammonia from nitrogen and hydrogen is 1.6 × 102. what is the form of the equilibri

Nimfa-mama [501]

Answer: The expression for equilibrium constant is $\frac{[NH_3]^2}{[H_2]^3[N_2]}$

Explanation: Equilibrium constant is the expression which relates the concentration of products and reactants preset at equilibrium at constant temperature. It is represented as $k_c$

For a general reaction:

$aA+bB\rightleftharpoons cC+dD$

The equilibrium constant is written as:

$k_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

Chemical reaction for the formation of ammonia is:

$N_2+3H_3\rightleftharpoons 2NH_3$

$k_c=1.6\times 10^2$

Expression for $k_c$ is:

$k_c=\frac{[NH_3]^2}{[H_2]^3[N_2]}$

$1.6\times 10^2=\frac{[NH_3]^2}{[H_2]^3[N_2]}$

8 0

3 years ago

Suppose NAD is unavailable because NADH cannot be oxidized due to a mutation in the NADH dehydrogenase (Complex I). If FAD could

Dovator [93]

Answer:

FAD substitution will produce 28 ATP instead of 36.

Explanation:

NAD and FAD are coenzymes involved in reversible oxidation and reduction reactions. These compounds are also known as electron carriers. However NADH produce 3 electrons in electron transport chain and FADH2 produce 2 electron beacuase it transfer the electrons to second complex in ETC.

Normal prduction of ATP from glucose;

2 cytoplasmic NADH formed in glycolysis Each yields 2 ATP +4

2 NADH formed in the oxidation of pyruvate Each yields 3 ATP +6

2 FADH2 formed in the citric acid cycle Each yields 2 ATP +4

6 NADH formed in the citric acid cycle Each yields 3 ATP +18

2 ATP from glycolysis +2

2 ATP from citric acid cycle +2

Net yield ATP +36

C6H12O6 + 6 CO2 + 36 ADP + 36 Pi ⇒6 CO2 + 6 H2O + 36 ATP

If we replace the NAD with FAD the total ATP production would be.

2 cytoplasmic FADH2 formed in glycolysis Each yields 2 ATP +4

2 FADH2 formed in the oxidation of pyruvate Each yields 3 ATP +4

2 FADH2 formed in the citric acid cycle Each yields 2 ATP +4

6 FADH2 formed in the citric acid cycle Each yields 2 ATP +12

2 ATP from glycolysis

2 ATP from citric acid cycle +2

<u>Net yield ATP +28</u>

C6H12O6 + 6 CO2 + 28ADP + 28 Pi ⇒6 CO2 + 6 H2O + 28 ATP

7 0

3 years ago