In writing chemical reactions, it is important that you know the chemical formula of each substance and in balancing them, it should be that the number of each element in both side are equal.

2K(s) + 2H2O(l) = 2KOH(aq) + H2(g)

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Consider the following three samples. A. A sample containing 180 g glucose (C6H12O6) B. A sample containing 90 g glucose and 90

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Answer:

E) All three samples have the same number of hydrogen atoms

Explanation:

The statements are:

A) Sample A has more hydrogen atoms than sample B or sample C.

B) Sample B has more hydrogen atoms than sample A or sample C.

C) Sample C has more hydrogen atoms than sample A or sample B

D) Both samples A and C have the same number of hydrogen atoms, but more than in sample B.

E) All three samples have the same number of hydrogen atoms

Hydrogens in sample A are:

180g × (1mol Glucose / 180.156g) × (12mol H / 1 mol Glucose) = 12 moles of H

Hydrogens in sample B are:

90g Glucose × (1mol Glucose / 180.156g) × (12mol H / 1 mol Glucose) = 6 moles of H

90g mannose× (1mol Mannose / 180.156g) × (12mol H / 1 mol Glucose) = 6 moles of H

Total moles: 12

Hydrogens in sample C are:

180g × (1mol Mannose / 180.156g) × (12mol H / 1 mol Glucose) = 12 moles of H

Thus, right answer is:

E) All three samples have the same number of hydrogen atoms

I hope it helps!

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