Answer:
1.15 m/s
Explanation:
Part of the question is missing. Found the missing part on google:
"1. A hanging mass of 1500 grams compresses a spring 2.0 cm. Find the spring constant in N/m."
Solution:
First of all, we need to find the spring constant. We can use Hooke's law:
where
is the force applied to the spring (the weight of the hanging mass)
x = 2.0 cm = 0.02 m is the compression of the spring
Solving for k, we find the spring constant:
In the second part of the problem, the spring is compressed by
x = 3.0 cm = 0.03 m
So the elastic potential energy of the spring is
This energy is entirely converted into kinetic energy of the cart, which is:
where
m = 500 g = 0.5 kg is the mass of the cart
v is its speed
Solving for v,
Answer:
The momentum principle tells us that impulse transfers momentum to an object. If an object has 2 kg m/s of momentum, a 1 kg m/s impulse delivered to the object increases its momentum to 3 kg m/s. That is, pfx = pix + Jx. Just as we did with energy, we can represent this “momentum accounting” with a momentum bar chart.
<span>One property of an electron is that it has a net charge of -1. This is because the magnitude of the electric charge of an electron offsets the elementary electric charge of a proton.</span>
You have to find the calculate<span> the circumference first then you can just multiply the diameter by π, which is about 3.142. That gives you the distance for each </span>revolution<span>. Then you can multiply by the </span>number of revolutions<span> per minute.
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