Power = energy/time=20/4=5.0
Answer:
Solution given:
height [H]=25m
initial velocity [u]=8.25m/s
g=9.8m/s
now;
a. How long is the ball in flight before striking the ground?
Time of flight =?
Now
Time of flight=![\sqrt{\frac{2H}{g}}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B2H%7D%7Bg%7D%7D)
substituting value
- =
![\sqrt{\frac{2*25}{9.8}}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B2%2A25%7D%7B9.8%7D%7D)
- =2.26seconds
<h3>
<u>the ball is in flight before striking the ground for 2.26seconds</u>.</h3>
b. How far from the building does the ball strike the ground?
<u>H</u><u>o</u><u>r</u><u>i</u><u>z</u><u>o</u><u>n</u><u>t</u><u>a</u><u>l</u><u> </u>range=?
we have
Horizontal range=u*![\sqrt{\frac{2H}{g}}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B2H%7D%7Bg%7D%7D)
<h3>
<u>The ball strikes 18.63m far from building</u>. </h3>
Each capacitor carry the same charge 'q'.
Discussion:
The voltage from the battery is distributed equally across all of the capacitors when they are linked in series. The three identical capacitors' combined voltage is computed as follows:
= V₁ +V₂ +V₃
This voltage may also be calculated using capacitance and charge;
V = Q/ C
= V₁ +V₂ +V₃
Provided that the total charge is 'q', hence the total voltage can be expressed as:
= (Q/C₁) + (Q/C₂) + (Q/C₃) = Q(1/C₁ +1/C₂ +1/C₃)
Therefore from the above explanation, it is concluded that each and every capacitor carry same charge 'q'.
Learn more about the capacitor here:
brainly.com/question/17176550
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Answer:If the kinetic and potential energy in a system are equal, then the potential energy increases. ... Stored energy decreases. Energy of motion decreases. Total energy decreases
Explanation: