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RUDIKE [14]
3 years ago
13

The ion formed by an atom of tin when it loses four electrons is called what?

Chemistry
1 answer:
MatroZZZ [7]3 years ago
6 0

free radical , prositron or proton .

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Помогите срочно сделать по химии промежуточную отестацию за 8 класс
il63 [147K]

Answer:

This is site for English  speakers.  Этот сайт на английском, поэтому вопрос могут удалить

Explanation:

1. 2)

2. 3)

3. 4) Sr

4. 3)

5. 4)

6. 2)

7. 1)

8. 4)

9. 3)

10. 3)

11. SO3, H2SO4, Na2SO4

12.

A) оксид меди (II) 2) CuO

Б) хлорид меди(II) 4) CuCl2

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13.

1. Fe+HCl= б) FeCl 2 +H 2

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14. 2Ca + O2 = 2CaO

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6 0
3 years ago
How many miles of C are in 32.6 g of C2H6
sammy [17]
32.6 grams divided by the molar mass of C2H6, which is 18.0584g/mol = 1.8 moles of C2H6.

As there are two carbon atoms per C2H6, we must multiply the number of moles of C2H6 by 2 to get the number of moles of Carbon which is 3.6 moles.
The answer is 3.6 moles.

Hope this helps.

(Sorry for previously incorrect answer)
5 0
3 years ago
Which of the following distinguishes a nuclear reaction from a chemical reaction? a.It involves atoms.
MissTica
The option that distinguishes a nuclear reaction from a chemical reaction is D. there is a change in the nucleus.
During a nuclear reaction, two light nuclei combine in order to create a new, heavier one which is different than those two original ones and has additional particles that it didn't have originally. This is what makes the difference between these two reactions.
7 0
3 years ago
Read 2 more answers
The tosylate of (2R,3S)-3-phenylbutan-2-ol undergoes an E2 elimination on treatment with sodium ethoxide. Draw the structure of
andrezito [222]

Answer:

(R)-but-3-en-2-ylbenzene

Explanation:

In this reaction, we have a very <u>strong base</u> (<em>sodium ethoxide</em>). This base, will remove a hydrogen producing a double bond. We know that the reaction occurs through an <u>E2 mechanism</u>, therefore, the hydrogen that is removed must have an <u>angle of 180º</u> with respect to the leaving group (the "OH"). This is known as the <u>anti-periplanar configuration</u>.

The hydrogen that has this configuration is the one that placed with the <u>dashed bond</u> (<em>red hydrogen</em>). In such a way, that the base will remove this hydrogen, the "OH" will leave the molecule and a double bond will be formed between the methyl and the carbon that was previously attached to the "OH", producing the molecule (R) -but-3- en-2-ylbenzene.

See figure 1

I hope it helps!

6 0
3 years ago
What type of isomers are ch3ch2och3 and ch3ch2ch2oh?
N76 [4]
Functional isomers
because the first one is an ether and the other one an alcohol
4 0
4 years ago
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