Answer:

Explanation:
= Initial concentration = 1.28 M
= Final concentration = ![0.17[A]_0](https://tex.z-dn.net/?f=0.17%5BA%5D_0)
k = Rate constant = 0.0632 s
t = Time taken
For first order reaction we have the relation
![kt=\ln\dfrac{[A]_0}{[A]}\\\Rightarrow t=\dfrac{\ln\dfrac{[A]_0}{[A]}}{k}\\\Rightarrow t=\dfrac{\ln\dfrac{[A]_0}{0.17[A]_0}}{0.0632}\\\Rightarrow t=28.037\ \text{s}](https://tex.z-dn.net/?f=kt%3D%5Cln%5Cdfrac%7B%5BA%5D_0%7D%7B%5BA%5D%7D%5C%5C%5CRightarrow%20t%3D%5Cdfrac%7B%5Cln%5Cdfrac%7B%5BA%5D_0%7D%7B%5BA%5D%7D%7D%7Bk%7D%5C%5C%5CRightarrow%20t%3D%5Cdfrac%7B%5Cln%5Cdfrac%7B%5BA%5D_0%7D%7B0.17%5BA%5D_0%7D%7D%7B0.0632%7D%5C%5C%5CRightarrow%20t%3D28.037%5C%20%5Ctext%7Bs%7D)
Time taken to reach the required concentration would be
.
First convert the kg to g ----- 0.03kg = 30g
Then divide the mass by the volume ----- 30g ÷ 25mL = 1.2
The density is 1.2g/mL<span />
Answer:
The value is 
Explanation:
From the question we are told that
The bond length is
The bond dipole moment is 
Generally the dipole moment is mathematically represented as

Here Q is the partial negative charge on the bromine atom
So

=> 
=> 
Generally
1 electronic charge(e) is equivalent to 
So x electronic charge(e) is equivalent to 
=> 
=> 
Answer:
Both student have same percent error.
Explanation:
Given data:
Actual mass of object = 0.54 g
Measured value by one student = 0.59 g
Measured value by second student = 0.49 g
Percent error = ?
Solution:
Formula
Percent error = (measured value - actual value / actual value) × 100
Percent error of first student:
percent error = (0.59 g - 0.54 / 0.54 ) ×100
percent error = 9.3 %
Percent error of second student:
Percent error = (0.49 g - 0.54 / 0.54 ) ×100
Percent error = - 9.3 %
Both student have same percent error. The only difference is that first student measure the greater value then actual value and second student measure the less value then actual, however difference was same and gives same percent error.
Your answer for this would be A. Mixtures cannot be separated by physical meansA pure substance is heterogeneous.
Hope This Helps :)