Answer:
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Answer:
Explanation:
Using the formula to calculate the maximum height
H = u²/2g
u is the initial velocity = 18m/s
g is the acceleration due to gravity = 9.81
H = 18²/2(9.81)
H = 324/19.62
H = 16.51m
The maximum height in which the ball reached from the ground = 85m + 16.51m = 101.5m
b) Time of fight = 2u/g
T = 2(18)/g
T = 36/9.81
T = 3.67s
It took the ball 3.67s later to reach the ground
3) To get the final velocity of the ball as it hits the ground, we need to calculate the horizontal component of the velocity,
Ux = Ucosθ
ux = 18cos 90 (angle of launch is 90 since the ball is thrown vertically upwards)
Ux = 18(0)
Ux = 0m/s
Hence the final velocity of the ball as it hits the ground is 0m/s
I think centripetal force ☺
I’m pretty sure A is the answer
The combined speed of the plane and the wind is 249.35 km/h.
<h3>
Relative speed</h3>
The relative speed of the plane due to speed of the wind is calculated as follows;
Let the direction of the plane be horizontal direction.
<h3>Speed of the wind</h3>
The speed of the wind is calculated as follows;
<h3>Combined speed</h3>
The combined speed of the plane and the wind is calculated as follows;
V = 275 km/h - 25.65 km/h
V = 249.35 km/h
Thus, the combined speed of the plane and the wind is 249.35 km/h.
Learn more about relative speed here: brainly.com/question/17228388