Which best describes a reference frame?
1 answer:
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Answer:
magnetic field will allow the electron to go through 2 x T k
Explanation:
Given data in question
velocity = 5.0 ×
electric filed =
To find out
what magnetic field will allow the electron to go through, undeflected
solution
we know if electron move without deflection i.e. net force is zero on electron and we can say both electric and magnetic force equal in magnitude and opposite in directions
so we can also say
F(net) = Fe + Fb i.e. = 0
q V B + q E = 0
q will be cancel out
+ 5e + 7i × B = 0
B = 2 x T k
The correct answer is
<span>force per unit charge.
In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span>
where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.
<span>force per unit charge.
In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span>
where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.
Missing figure: http://d2vlcm61l7u1fs.cloudfront.net/media/f5d/f5d9d0bc-e05f-4cd8-9277-da7cdda3aebf/phpJK1JgJ.png
Solution:
We need to find the magnitude of the resultant on both x- and y-axis.
x-axis) The resultant on the x-axis is
in the positive direction.
y-axis) The resultant on the y-axis is
in the positive direction.
Both Fx and Fy are positive, so the resultant is in the first quadrant. We can find the angle and so the direction using
from which we find
Solution:
We need to find the magnitude of the resultant on both x- and y-axis.
x-axis) The resultant on the x-axis is
in the positive direction.
y-axis) The resultant on the y-axis is
in the positive direction.
Both Fx and Fy are positive, so the resultant is in the first quadrant. We can find the angle and so the direction using
from which we find