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3 years ago

8

A car is traveling north at 17.7 m/s . After 6 it’s velocity is 141 in the same direction. Find the magnitude and direction of t

he cars average acceleration

1 answer:

Furkat [3]3 years ago

3 0

By equation of motion we have v = u + at

Where u = Initial velocity, v = final velocity, t = time taken and a = acceleration

Here v = 141 m/s, u = 17.7 m/s and t = 6 s

On substitution we will get

141 = 17.7+ 6a

So, a = (141-17.7)/6 = 20. 55 m/ $s^{2}$

Aceeleration = 20. 55 m/ $s^{2}$ along north direction.

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2 years ago

A car is traveling up a hill that is inclined at an angle θ above the horizontal. Determine the ratio of the magnitude of the no

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3 years ago

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