Answer:
= 1220 nm
= 1.22 μm
Explanation:
given data:
wavelength 
distance of screen from slits D = 3 m
1st order bright fringe is 4.84 mm
condition for 1 st bright is
---( 1)
and
= 0.0924 degrees
plug theta value in equation 1 we get
condition for 1 st dark fringe
= 2λ since from eq (1)
= 1220 nm
= 1.22 μm
geyser.........................................
Answer:
Kinetic energy can be solved by using the following formula: Kinetic energy = (1/2)*m*v^2
Explanation:
Answer:
1.28 m, 14 m/s
Explanation:
At the maximum height, the velocity is 0.
Given:
a = -9.8 m/s²
v₀ = 5.00 m/s
v = 0 m/s
x₀ = 0 m
Find:
x
v² = v₀² + 2a(x - x₀)
(0 m/s)² = (5.00 m/s)² + 2(-9.8 m/s²) (x - 0 m)
x = 1.28 m
The maximum speed is at the bottom of the well.
Given:
a = -9.8 m/s²
v₀ = 5.00 m/s
x₀ = 0 m
x = -8.5 m
Find:
v
v² = v₀² + 2a(x - x₀)
v² = (5.00 m/s)² + 2(-9.8 m/s²) (-8.5 m - 0 m)
v = -13.8 m/s
Rounded to 2 sig-figs, the maximum speed is 14 m/s.
Answer:
15?6 and 17 plus 18 equals e b d f g so correct
Explanation:
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