Question

A probe orbiting Venus exerts a gravitational force of 2.58 × 103 N on Venus. Venus has a mass of 4.87 × 1024 kg. The mass of the probe is 655 kilograms.

Answer 1

Answer:

The radius of the probe from the center of Venus is $9.08\times10^{6}\ m$.

Explanation:

Given that,

Gravitational force$F_{g} = 2.58\times10^{3}\ N$

Mass of Venus $M= 4.87\times10^{24}\ kg$

Mass of probe m= 655 kg

Suppose we find the radius of the probe from the center of Venus

We need to calculate the radius

Using gravitational force

$F_{g}=\dfrac{GmM}{r^2}$

Put the value into the formula

$2.58\times10^{3}=\dfrac{6.67\times10^{-11}\times655\times4.87\times10^{24}}{r^2}$

$r^2=\dfrac{6.67\times10^{-11}\times655\times4.87\times10^{24}}{2.58\times10^{3}}$

$r=\sqrt{\dfrac{6.67\times10^{-11}\times655\times4.87\times10^{24}}{2.58\times10^{3}}}$

$r=9.08\times10^{6}\ m$

Hence, The radius of the probe from the center of Venus is $9.08\times10^{6}\ m$.

Answer 2

The correct answer is:

9.08 x 10⁶ meters.

Explanation:

Fg = 2.58 x 10³ N

Mv = 4.87 x 10²⁴ Kg

Md = 655 Kg

So, Fg = G Mv Mp / r²

By putting in the values,

r² = 8.2466 x 10¹³

r = 9.08 x 10⁶ meters.