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3 years ago

How many grams of Ag2CO3 are required to reacr with 28.5 mL of 1.00 M NaOH solution?

1 answer:

8 0

The reaction between Ag2CO3 and NaOH is shown by the equation below
Ag2CO3 + NaOH = Ag2O + Na2CO3 +H2O
we can determine the number of mole of sodium hydroxide
by (2.85 ml × 1) ÷ 1000 ml , since according to molarity 1 mole is contained in 100ml.
we get 0.00285 moles of NaOH
Using the mole ratio we can get the moles of Ag2CO3
Mole ratio: Ag2NO3 : NaOH = 1:1
Therefore, the moles of Ag2CO3 will be 0.00285 moles
but 1 mole of silver carbonate is equivalent to 275.8 g
Thus the mass will be calculated by 0.00285 moles × 275.8g = 0.78603g
Mass of silver carbonate required will be 0.78603g

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Read 2 more answers

? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2

Novay_Z [31]

Data:
$M_{concentrated} = 2.5\:mol$
$V_{concentrated} = ?$
$M_{dilute} = 0.50\:mol$
$V_{dilute} = 100\:mL\to0.100\:L$

Formula: Dilution Calculations

 $M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}$

Solving:


$M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}$
$2.5 * V_{concentrated} = 0.50 * 0.100$
$2.5V_{concentrated} = 0.05$
$V_{concentrated} = \frac{0.05}{2.5}$
$\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark$

3 0

3 years ago

Calculate the mass of sodium azide required to decompose and produce 2.104 moles of nitrogen. Refer to the periodic table to get

Alexxx [7]

91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.

Explanation:

2NaN3======2Na+3N2

This is the balanced equation for the decomposition and production of sodium azide required to produce nitrogen.

From the equation:

2 moles of NaNO3 will undergo decomposition to produce 3 moles of nitrogen.

In the question moles of nitrogen produced is given as 2.104 moles

so,

From the stoichiometry,

3N2/2NaN3=2.104/x

= 3/2=2.104/x

3x= 2*2.104

= 1.4 moles

So, 1.4 moles of sodium azide will be required to decompose to produce 2.104 moles of nitrogen.

From the formula

no of moles=mass/atomic mass

mass=no of moles*atomic mass

1.4*65

= 91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.

4 0

3 years ago