The reaction between Ag2CO3 and NaOH is shown by the equation below Ag2CO3 + NaOH = Ag2O + Na2CO3 +H2O we can determine the number of mole of sodium hydroxide by (2.85 ml × 1) ÷ 1000 ml , since according to molarity 1 mole is contained in 100ml. we get 0.00285 moles of NaOH Using the mole ratio we can get the moles of Ag2CO3 Mole ratio: Ag2NO3 : NaOH = 1:1 Therefore, the moles of Ag2CO3 will be 0.00285 moles but 1 mole of silver carbonate is equivalent to 275.8 g Thus the mass will be calculated by 0.00285 moles × 275.8g = 0.78603g Mass of silver carbonate required will be 0.78603g
