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gtnhenbr [62]
3 years ago
11

1.Which is the lowest level of organization for the system in a human

Chemistry
1 answer:
elena55 [62]3 years ago
5 0

Answer:

brain cell

Explanation:

hope this helps :)

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prease tell me the answer. When a liquid changes to a gas below the surface of a liquid as well as at the surface, it is called
Anton [14]
Its called freezing, the change from a liquid to a gas is called vaporization
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Calculate the ph of a buffer solution that contains 0.25 m benzoic acid (c6h5co2h) and 0.15 m sodium benzoate (c6h5coona). (ka =
zhannawk [14.2K]
Hello!

To solve this problem we'll use the Henderson-Hasselbach equation, but first we need the vale for the pKa of Benzoic acid, which is pKa= -log(Ka)=4,19

Now, we apply the equation as follows:

pH=pKa + log ( \frac{[C_6H_5COONa]}{[C_6H_5COOH]} )=4,19+log( \frac{0,15M}{0,25M} )=3,97

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3 years ago
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How are elements arranged in the periodic table?
zepelin [54]
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3 years ago
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Use the periodic table to determine what element cesium-135 () becomes after beta decay.
bonufazy [111]

Answer:

D. _{56}^{135}\text{Ba}

Explanation:

Your unbalanced nuclear equation is

_{55}^{135}\text{Cs} \longrightarrow ? + _{-1}^{0}\text{e}

It is convenient to replace the question mark by an atomic symbol, _{x}^{y}\text{Z}, where <em>x</em> = the atomic number, <em>y</em> = the mass number, and <em>Z</em> = the symbol of the element .

Then your equation becomes

_{55}^{135}\text{Cs} \longrightarrow _{x}^{y}\text{Z} + _{-1}^{0}\text {e}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

55 = <em>x</em> - 1, so <em>x</em> = 55 + 1 = 56

135 = <em>y</em> + 0, so <em>y</em> = 135

Element 56 is barium, so the nuclear equation becomes

_{55}^{135}\text{Cs} \longrightarrow _{56}^{135}\text{Ba} + _{-1}^{0}\text{e}

4 0
3 years ago
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an oven adds 2260 j heat to a zinc tray that weighs 195g of the tray starts at 25 what is the final temperature of the tray
choli [55]
Divide the grams by 25 to 195 then times it in decimal
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