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Marysya12 [62]
1 year ago
8

Romeo and Juliet are sitting on a balcony 1.5 meters apart. If Romeo has a mass of 61.6 Kg and Juliet has a mass of 48.8 kg. Wha

t is the attractive force between them?
Physics
1 answer:
Setler79 [48]1 year ago
4 0
\begin{gathered} m_{Romeo}=61.6\text{ kg} \\ m_{Juliet}=48.8\text{ kg} \\ r=1.5\text{ m} \\ G=6.673x10^{-11}Nm^2/kg^2 \\ F=G*\frac{m_{Juliet}m_{Romeo}}{r^2} \\  \\ F=\left(6.673x10^{-11}Nm^2/kg^2\right)\frac{\left(48.8\text{ kg}\right)\left(61.6\text{ kg}\right)}{\left(1.5\text{ m}\right)^2} \\  \\ F=8.91x10^{-8}N \\ The\text{ attractive force is 8.91x10}^{-8}\text{N} \end{gathered}

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A car travels across Texas m miles at the rate of t miles per hour. How many hours does the trip take??
Marianna [84]

Answer: The trip takes \frac{m}{t}hours

Explanation:

Velocity V is the variation of the position of a body (distance traveled d) with time T:

V=\frac{d}{T}

In this case, the car travels a distance d=m miles at a velocity V=t \frac{miles}{hour} and we need to find the time it takes the trip.

Isolating  T:

T=\frac{d}{V}=\frac{m miles}{t \frac{miles}{hour}}

Finally:

T=\frac{m}{t}hours

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3 years ago
One nanometer is equal to how many centimeters?
Neko [114]
One nanometer = 1e-7
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3 years ago
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Two dump trucks each have a mass of 1,500 kg. The distance of the dump truck
xxTIMURxx [149]

Answer:

6.00 x 10⁻⁸N

Explanation:

Given parameters:

Mass of each dump trucks  = 1500kg

Distance between them  = 50m

Unknown:

New gravitational force between them = ?

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From Newton's law of universal gravitation,

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F is the gravitational force

G is the universal gravitation constant

m is the mass

r is the distance

           F  = \frac{6.67 x 10^{-11} x 1500  x 1500}{50^{2} }    = 6.00 x 10⁻⁸N

4 0
3 years ago
2.
saul85 [17]

Answer:

<u>B</u>

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Planets have different year lengths because it depends how far they revolve from a celestial body. Each planet has its own orbital period. Planets closer to the star will have a lower orbital period compared to the ones that lie far away from it.

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1 year ago
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Find expressions for the force needed to bring an object of mass m from rest to speed v in time t. express your answer in terms
VARVARA [1.3K]
Good morning.

We have that:

\mathsf{V = a\cdot t} , since we have rest in the inicial time.

The acceleration can be found with Newton's Law:

\mathsf{F = m\cdot a\iff a = \dfrac{F}{m}}

Now we put the acceleratin in the velocity equation:

\mathsf{V = \dfrac{F}{m} \cdot t}

We want the force, so, let's isolate F:

\mathsf{V\cdot m = F\cdot t}\\ \\ \\ \boxed{\mathsf{F = \dfrac{V\cdot m}{t}}}

3 0
2 years ago
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