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4 years ago

Which statement describes the influence of latitude on temperature?

Physics

2 answers:

Agata [3.3K]4 years ago

8 0

Latitudes are angles that range from zero degrees at the equator to 90 degrees North or South at the poles.

Temperature is inversely related to latitude. As latitude increases, the temperature falls, and vice versa.

Generally, around the world, it gets warmer towards the equator and cooler towards the poles.

-Dominant- [34]4 years ago

3 0

The correct answers are: •Latitude determines the duration of daylight.
•Latitude creates polar and temperate zones.
•Latitude influences the movement of warm and cool air over land.

Latitude is defined as the distance of a place on the earth surface from the equator. So, from the poles to the Equator the amount of sunlight changes in (decreases from season to season). Different latitudes receive different amounts of sunlight, so higher latitudes receive less heat than lower latitude areas (nearer the equator). Also, the angle at which the sun's rays strike the earth's surface is dependent on latitude.

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3 years ago

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3 years ago

Two soccer players start from rest, 36 m apart. They run directly toward each other, both players accelerating. The first player

Cerrena [4.2K]

A) Both players are moving by uniformly accelerated motion, and we can write the position at time t of each of the two players as follows:
$x_1(t)= \frac{1}{2}a_1 t^2$
$x_2(t)=d- \frac{1}{2}a_2 t^2$
where
$a_1 = 0.58 m/s^2$ is the acceleration of the first player
$a_2=0.42 m/s^2$ is the acceleration of the second player
$d=36 m$ is the initial distance between the two players
and where I put a negative sign in front of the acceleration of the second player, since he's moving in the opposite direction of the first player.

The time t at which the two players collide is the time t at which $x_1 = x_2$ , therefore:
$\frac{1}{2}a_1 t^2 = d- \frac{1}{2}a_2 t^2$
from whic we find
$t= \sqrt{ \frac{2d}{a_1+a_2} }= \sqrt{ \frac{2 \cdot 36 m}{0.58 m/s^2+0.42 m/s^2} }=8.5 s$

b) We can use the equation of $x_1(t)$ to find how far the first player run in t=8.5 s:
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8 0

3 years ago

What is the pressure drop due to the Bernoulli Effect as water goes into a 3.00-cm-diameter nozzle from a 9.00-cm-diameter fire

Marianna [84]

Answer:

The pressure and maximum height are $1.58\times10^{6}\ N/m^2$ and 161.22 m respectively.

Explanation:

Given that,

Diameter = 3.00 cm

Exit diameter = 9.00 cm

Flow = 40.0 L/s²

We need to calculate the pressure

Using Bernoulli effect

$P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho g h_{1}=P_{2}+\dfrac{1}{2}\rho v_{2}^2+\rho g h_{2}$

When two point are at same height so ,

$P_{1}+\dfrac{1}{2}\rho v_{1}^2=P_{2}+\dfrac{1}{2}\rho v_{2}^2$ ....(I)

Firstly we need to calculate the velocity

Using continuity equation

For input velocity,

$Q=A_{1}v_{1}$

$v_{1}=\dfrac{Q}{A_{1}}$

$v_{1}=\dfrac{40.0\times10^{-3}}{\pi\times(1.5\times10^{-2})^2}$

$v_{1}=56.58\ m/s$

For output velocity,

$v_{2}=\dfrac{40.0\times10^{-3}}{\pi\times(4.5\times10^{-2})^2}$

$v_{2}=6.28\ m/s$

Put the value into the formula

$P_{1}-P_{2}=\dfrac{1}{2}\rho(v_{1}^2-v_{2}^2)$

$\Delta P=\dfrac{1}{2}\times1000\times(56.58^2-6.28^2)$

$\Delta P=1.58\times10^{6}\ N/m^2$

(b). We need to calculate the maximum height

Using formula of height

$\Delta P=\rho g h$

Put the value into the formula

$1.58\times10^{6}=1000\times9.8\times h$

$h=\dfrac{1.58\times10^{6}}{1000\times9.8}$

$h=161.22\ m$

Hence, The pressure and maximum height are $1.58\times10^{6}\ N/m^2$ and 161.22 m respectively.

8 0

4 years ago

name the device used often to change the resistance without changing the voltage source in an electric circuit

timofeeve [1]

<em>the devices which are used to change the resistance in a circuit are called
<u>resisitors...
</u>the fact that they effect the voltage or not simply depends upon the type of resistor used in the circuit ...:)

</em>

5 0

3 years ago

Read 2 more answers