Answer: n=4
Explanation:
We have the following expression for the volume flow rate 
of a hypodermic needle:
(1)
Where the dimensions of each one is:
Volume flow rate 
Radius of the needle 
Length of the needle 
Pressures at opposite ends of the needle 
and 
Viscosity of the liquid 
We need to find the value of 
whicha has no dimensions, and in order to do this, we have to rewritte (1) with its dimensions:
(2)
We need the right side of the equation to be equal to the left side of the equation (in dimensions):
(3)
(4)
As we can see must be 4 if we want the exponent to be 3:
(5)
Finally:
(6)
Answer:
B.
Venus is the same size and density.
Explanation:
It is becuase venus has the same size and density as earth
Answer:
5 ) The mass, 6) with lubrication and using surfaces that are not rough
Explanation:
5) If two bodies are held regardless of their densities and can be combined by some chemical or physical process, the only physical property to be modified will be the mass of the resulting body.
8)
Friction depends on the contact between two surfaces and when a body has a relative motion with respect to a contact surface. In order to reduce friction the contact surface must be lubricated, also the friction depends on the coefficient of friction between surfaces and the normal force exerted by the surface parallel to the area of contact with the body. Mathematically it can be expressed with the following equation.
![F_{f} = u*N\\where:\\u = friction coefficient\\N = normal force [Newtons]\\F_{f}= friction force [Newtons]](https://tex.z-dn.net/?f=F_%7Bf%7D%20%3D%20u%2AN%5C%5Cwhere%3A%5C%5Cu%20%3D%20friction%20coefficient%5C%5CN%20%3D%20normal%20force%20%5BNewtons%5D%5C%5CF_%7Bf%7D%3D%20friction%20force%20%5BNewtons%5D)
Answer:
q = 4.04×10^-12C
n = 2.53×10^7
Explanation:
1. Electrostatic force on charge due to electrical field E is F = qE
Gravitational force due to weight of drop of mass M is F = mg, when net force is zero we have to find the charges on the drop.
2. Charge on drop: since gravitational force is acting downward, electric field is acting upward and we equate both equations.
Therefore, Fg = Fe
qe = mg
q = mg/E
q = 3.50×10^-9kg×9.8m/s²/8480N/c
q = 4.04 × 10^-12
3. Number of protons by quantitization law
n = q/e
n = 4.04× 10^-12/8480
n = 2.53× 10^7
Explanation:
The given data is as follows.
F = 
q = 
v = 385 m/s
= 0.876
Now, we will calculate the magnitude of magnetic field as follows.
B = 
= 
= 
T
= 10.65 T
Thus, we can conclude that magnitude of the magnetic field is 10.65 T.
