To solve this problem it is necessary to apply the fluid mechanics equations related to continuity, for which the proportion of the input flow is equal to the output flow, in other words:
We know that the flow rate is equivalent to the velocity of the fluid in its area, that is,
Where
V = Velocity
A = Cross-sectional Area
Our values are given as
Since there is continuity we have now that,
Therefore the speed of the water's house supply line is 0.347m/s
Answer:
the number of turns in the primary coil is 13000
Explanation:
Given the data in the question;
V₁ = 13000 V
V₂ = 120 V
N₁ = ?
N₂ = 120 turns
the relation between the voltages and the number of turns in the primary and secondary coils can be expressed as;
V₁/V₂ = N₁/N₂
V₁N₂ = V₂N₁
N₁ = V₁N₂ / V₂
so we substitute
N₁ = (13000 V × 120 turns) / 120 V
N₁ = 1560000 V-turns / 120 V
N₁ = 13000 turns
Therefore, the number of turns in the primary coil is 13000
Answer:
The volt meets the.... (I can't think of a catchy name for a light bulb) Think about it though
The maximum static force that can be applied is equal to the normal force*the frictional force. the normal force on the box is equal to mg since the floor is flat using 9.81m/s^2 for gravity 12kg*9.81m/s^2 = 118N multiplying the normal force by the frictional force you get a 118*.42= 49.6N so overcome the force of static friction on the box a minimum of 49.6N would need to be applied.
Answer:
a = 177.77 [m/s^2]
Explanation:
Este es un problema relacionado con la segunda ley de Newton. La cual nos dice que la sumatoria de fuerzas aplicada sobre un cuerpo debe ser igual al producto de la masa por la aceleración.
De esta manera tenemos:
F = m*a
F = fuerza = 80 [N]
m = masa = 0.45 [kg]
80 = 0.45 * a
a = 80 / 0.45
a = 177.77 [m/s^2]
