Answer:
Explanation:
GIVEN DATA:
Total mass ( rider + his tube) = 80 kg
tension Force = 360 N
height of slope = 30 m
length of slope = 120 m
we know that thermal energy is given as
E_{th} = W- Ug
W= F*d = (360N*120m)= 43200 J
Ug= m*g*h = (80kg*9.8m/s2*30m) = 23520 J
Qualitative data would be taken in this investigation. This is because the effect of the cold temperature on the leaves can not be measured quantitatively, but can be observed in the leaves' appearances. The qualitative data may include how green the leaf looks or how upright and rigid it is. The readings would be taken for leaves with and without snow.
Answer:
Initial velocity, U = 28.73m/s
Explanation:
Given the following data;
Final velocity, V = 35m/s
Acceleration, a = 5m/s²
Distance, S = 40m
To find the initial velocity (U), we would use the third equation of motion.
V² = U² + 2aS
Where;
V represents the final velocity measured in meter per seconds.
U represents the initial velocity measured in meter per seconds.
a represents acceleration measured in meters per seconds square.
S represents the displacement measured in meters.
Substituting into the equation, we have;
35² = U + 2*5*40
1225 = U² + 400
U² = 1225 - 400
U² = 825
Taking the square root of both sides, we have;
Initial velocity, U = 28.73m/s
Answer:
-64.0 m/s²
Explanation:
v = 32.0 t − 2.00 t³
Acceleration is the derivative of velocity.
a = dv/dt
a = 32.0 − 6.00 t²
At maximum displacement, v = 0 and a < 0.
v = 0
32.0 t − 2.00 t³ = 0
2.00 t (16.0 − t²) = 0
t = 0 or 4.00
When t = 0 s, a = 32.0 m/s².
When t = 4.00 s, a = -64.0 m/s².
The maximum displacement is at t = 4.00 s. Therefore, the acceleration at that moment is -64.0 m/s².