Answer:
a) θ = 2500 radians
b) α = 200 rad/s²
Explanation:
Using equations of motion,
θ = (w - w₀)t/2
θ = angle turned through = ?
w = final angular velocity = 1420 rad/s
w₀ = initial angular velocity = 420
t = time taken = 5s
θ = (1420 - 420) × 5/2 = 2500 rads
Again,
w = w₀ + αt
α = angular accelaration = ?
1420 = 420 + 5α
α = 1000/5 = 200 rad/s²
Answer:
c
Explanation:
cuz its informing the length of 5 and weight on 20N
Average speed = (total distance covered) / (time to cover the distance)
total distance covered = (4km + 2km + 1km) = 7 km
time to cover the distance = (32min + 22min + 16min) = 70 min
Average speed = (7 km) / (70 min)
Average speed = 0.1 km/minute
Explanation :
It is given that,
Diameter of the coil, d = 20 cm = 0.2 m
Radius of the coil, r = 0.1 m
Number of turns, N = 3000
Induced EMF, 
Magnitude of Earth's field, 
We need to find the angular frequency with which it is rotated. The induced emf due to rotation is given by :




So, the angular frequency with which the loop is rotated is 159.15 rad/s. Hence, this is the required solution.
Answer:
346.70015 m/s
Explanation:
In the x axis speed is

In the y axis

The resultant velocity is given by

The magnitude of the overall velocity of the hamper at the instant it strikes the surface of the ocean is 346.70015 m/s