Pulsar or also sometimes as a actively rotating accretion disc
To solve this problem it is necessary to apply the concepts related to gravity as an expression of a celestial body, as well as the use of concepts such as centripetal acceleration, angular velocity and period.
PART A) The expression to find the acceleration of the earth due to the gravity of another celestial body as the Moon is given by the equation
![g = \frac{GM}{(d-R_{CM})^2}](https://tex.z-dn.net/?f=g%20%3D%20%5Cfrac%7BGM%7D%7B%28d-R_%7BCM%7D%29%5E2%7D)
Where,
G = Gravitational Universal Constant
d = Distance
M = Mass
Radius earth center of mass
PART B) Using the same expression previously defined we can find the acceleration of the moon on the earth like this,
![g = \frac{GM}{(d-R_{CM})^2}](https://tex.z-dn.net/?f=g%20%3D%20%5Cfrac%7BGM%7D%7B%28d-R_%7BCM%7D%29%5E2%7D)
![g = \frac{(6.67*10^{-11})(7.35*10^{22})}{(3.84*10^8-4700*10^3)^2}](https://tex.z-dn.net/?f=g%20%3D%20%5Cfrac%7B%286.67%2A10%5E%7B-11%7D%29%287.35%2A10%5E%7B22%7D%29%7D%7B%283.84%2A10%5E8-4700%2A10%5E3%29%5E2%7D)
![g = 3.4*10^{-5}m/s^2](https://tex.z-dn.net/?f=g%20%3D%203.4%2A10%5E%7B-5%7Dm%2Fs%5E2)
PART C) Centripetal acceleration can be found throughout the period and angular velocity, that is
![\omega = \frac{2\pi}{T}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Cfrac%7B2%5Cpi%7D%7BT%7D)
At the same time we have that centripetal acceleration is given as
![a_c = \omega^2 r](https://tex.z-dn.net/?f=a_c%20%3D%20%5Comega%5E2%20r)
Replacing
![a_c = (\frac{2\pi}{T})^2 r](https://tex.z-dn.net/?f=a_c%20%3D%20%28%5Cfrac%7B2%5Cpi%7D%7BT%7D%29%5E2%20r)
![a_c = (\frac{2\pi}{26.3d(\frac{86400s}{1days})})^2 (4700*10^3m)](https://tex.z-dn.net/?f=a_c%20%3D%20%28%5Cfrac%7B2%5Cpi%7D%7B26.3d%28%5Cfrac%7B86400s%7D%7B1days%7D%29%7D%29%5E2%20%284700%2A10%5E3m%29)
![a_c = 3.34*10^{-5}m/s^2](https://tex.z-dn.net/?f=a_c%20%3D%203.34%2A10%5E%7B-5%7Dm%2Fs%5E2)
That statement is true
Retinal disparity : space between your eyes that allow binocular vision to create depth perception
Retinal Convergence : Space between your eyes that signal visual moves to the retina
They both will increases as an object get closer to the individual, allowing them acknowledge and observe the existence of the object
The question extends beyond what I already know.
The question makes me curious.
The statement above is FALSE.
The right hand rule is used in physics to predict the direction of the force on a charged object moving in a MAGNETIC FIELD. The right hand rule is used to relate the relationship between the magnetic field and the forces that are exerted on the moving objects in the field. Using the right hand rule, for a positively charged object that is moving in an electric field, the pointer finger will point in the direction the charged object is moving, the middle finger will point in the direction of the magnetic field and the thumb will point in the direction of the magnetic force that is pushing the charged object.