It is letter b which is Global Warming
B
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Answer:
amount of energy = 4730.4 kWh/yr
amount of money = 520.34 per year
payback period = 0.188 year
Explanation:
given data
light fixtures = 6
lamp = 4
power = 60 W
average use = 3 h a day
price of electricity = $0.11/kWh
to find out
the amount of energy and money that will be saved and simple payback period if the purchase price of the sensor is $32 and it takes 1 h to install it at a cost of $66
solution
we find energy saving by difference in time the light were
ΔE = no of fixture × number of lamp × power of each lamp × Δt
ΔE is amount of energy save and Δt is time difference
so
ΔE = 6 × 4 × 365 ( 12 - 9 )
ΔE = 4730.4 kWh/yr
and
money saving find out by energy saving and unit cost that i s
ΔM = ΔE × Munit
ΔM = 4730.4 × 0.11
ΔM = 520.34 per year
and
payback period is calculate as
payback period = 
payback period = 
payback period = 0.188 year
C, Land heats and cools faster than water!
<span>Correct pairs:
a man jogging in the park --> motion energy (the energy is the kinetic energy of the man, moving with speed v)
a fully charged camera battery --> electric potential energy (the battery is fully charged, so it can deliver electrical energy when the camera is turned on)
a stove burner that’s turned on --> radiant energy (the stove burner emits energy by radiation)
an apple on a tree --> gravitational potential energy (when the apple is on the tree, it has gravitational potential energy equal to U=mgh, where m is the apple's mass and h its height from the ground)
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