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qwelly [4]
2 years ago
14

A block with a mass of 0.28 kg is attached to a horizontal spring. The block is pulled back from its equilibrium position until

the spring exerts a force of 1.0 N on the block. When the block is released, it oscillates with a frequency of 1.2 Hz. How far was the block pulled back before being released?
Physics
1 answer:
krek1111 [17]2 years ago
8 0

Answer:

Explanation:

For spring

n=\sqrt{\frac{k}{m} }

where n is frequency of oscillation and k is force constant and m is mass

Putting the values

1.2=\sqrt{\frac{k}{.28} }

k = .4032 N/m

F= k x

where F is force , k is force constant and x is extension

Putting the given values

1 = .4032 x

x = 2.48 m

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