Answer:
There are 342 g/ 95. 2 g/m = 3.59 moles
Explanation:
MgCl2 → Molar mass is 95.2g g/m
This is the mass in one mol so to find out the moles in 342g we have to divide the mass between the molar mass.
342 g/ 95. 2 g/m = 3.59 moles
C. Homogeneous mixtures These alloys are homogeneous mixtures because they have a uniform composition throughout.
Answer:
can only accommodate 2 electrons
Answer:
0.435 M
Explanation:
In case of dilution , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = initial concentration ,
V₁ = initial volume ,
M₂ = final concentration , i.e. , concentration after dilution ,
V₂ = final volume .
from , the question ,
M₁ = 0.725 M
V₁ = 300 mL
M₂ = ?
V₂ = 300 mL + 200 mL = 500 mL
Since, the final volume of solution would be the summation of the initial and final volume.
Using the above formula , the molarity of the final solution after dilution , can be calculated as ,
M₁V₁ = M₂V₂
0.725 M * 300 mL = M₂ * 500mL
M₂ = 0.435 M
Answer:
D
Explanation:
Logitudinal waves also known as compression waves.