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Alekssandra [29.7K]
3 years ago
8

A current balance is a device to measure magnetic forces. It is constructed from two parallel coils, each with an average radius

of 12.5 cm. The lower coil rests on a balance; it has 20 turns and carries a constant current of 4.10 A. The upper coil, suspended 0.314 cm above the lower coil, has 50 turns and a current that can be varied. The reading of the balance changes as the magnetic force on the lower coil changes. What current is needed in the upper coil to exert a force of 1.30 N on the bottom coil

Physics
1 answer:
Andrei [34K]3 years ago
8 0

Answer: Current I = 6.34A

Explanation: Their will be attractive force if the currents in the coils are in the same direction, repulsive if in opposite directions.

The length to be considered is the circumference of the coils, 2π r , where r is the common radius.

In this question, currents will be I 1 I = n I and I 2 I = n I , where 1 n and 2 n are the numbers of turns in the coils and I is the common current.

Please find the attached file for the solution

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What kinds of information does the ALMA radio telescope provide?
zimovet [89]

Answer:

ALMA is a trans-formative radio telescope that can study cosmic light that straddles the boundary between radio and infrared. Most objects in the Universe emit this kind of energy, so the ability to detect it has been a driver for astronomers for decades.

Explanation:

7 0
3 years ago
A person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally
san4es73 [151]

Answer:

3.88 × 10^-4 m

Explanation:

Given that a  person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?

The total weight = 614 + 85

The total weight = 699N

Let the total area of contact = A

Pressure = Force / A

Substitute all the parameters into the formula

900000 = 699 /A

A = 699 / 900000

A = 7.77 × 10^-4 m

The area of contact between each tire and the ground will be = A/2

That is, 7.77 / 2 = 3.88 × 10^-4 m

Therefore, the area of contact between each tire and the ground is 3.88 × 10^-4 m approximately.

5 0
3 years ago
bothersome feature of many physical measurements is the presence of a background signal (commonly called "noise"). In Part 2.2.4
serious [3.7K]

Answer:

Incomplete question: "A signal of 20.7 mV is measured at a distance of 29 mm and 15.8 mV is measured at 32.5 mm. Correct the data for background and normalize the data to the maximum value. What is the normalized corrected value at 32.5 mm?"

The normalized corrected value at 32.5 mm is 0.1638

Explanation:

The corrected light measurement at 29 mm is equal to:

20.7 - 5.1 = 15.6 mV

The corrected light measurement at 32.5 mm is equal to:

15.6 - 5.1 = 10.5 mV

To normalize the data to its maximum value means that the maximum value must be calculated and the data must be scaled using that value, as in this case the maximum value is 15.6 mm, then the normalized corrected value at 32.5 mm is equal to:

10.5 * 15.6 = 163.8 = 0.1638

6 0
4 years ago
How is the physical property of density calculated?
torisob [31]

Answer:

The formula for density is d=M/V

Explanation:

where d is density, M id mass, V is volume.

3 0
3 years ago
Calculate the displacement and velocity at 2.00 s for a ball thrown straight up with an initialvelocity of 15.0 m/s. Take the po
Hunter-Best [27]

Answer:

The displacement, velocity and time is 20.4 m, -4.52 m/s and 3.624 sec.

Explanation:

Given that,

Initial velocity =15.0 m/s

Height = 10 m

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Using equation of motion

s=ut-\dfrac{1}{2}gt^2+s_{0}

Put the value into the formula

s=15t-\dfrac{1}{2}\times9.8\times t^2+10

At 2 sec,

s=15\times2-\dfrac{1}{2}\times9.8\times4+10

s=20.4\ m

We need to calculate the time

Using equation of motion again

s=15t-\dfrac{1}{2}\times9.8\times t^2+10

At ground s = 0,

15t-\dfrac{1}{2}\times9.8\times t^2+10=0

4.9t^2-15t-10=0

t = 3.624\ sec

Neglect the negative term because the time is not negative

We need to calculate the velocity

Using formula of velocity

v=u-gt

v=15-9.8\times3.624

v=-4.52\ m/s

Hence, The displacement, velocity and time is 20.4 m, -4.52 m/s and 3.624 sec.

5 0
3 years ago
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