It depends on the size of the star. If it's size was normal then it cools down into White dwarf, then a black dwarf. If a really huge star dies, then we can see a "Supernova" from that.
Hope this helps!!
A solar eclipse occurs when the moon crosses in front of the Sun, blocking some or all of its rays. A lunar eclipse happens when the moon is directly behind the earth, blocking the moon from receiving light. The only light comes from the light on earth's reflected shadow.
You can look at a lunar eclipse because there is very little light or none at all. You can't look at a solar eclipse because you are looking directly at the sun unless it is complete. Before totality, only some of the Sun is blocked, causing your pupils dilate to let in more light. Since they do this, more of the Sun's rays can be let in to the eye, which effectively allows your eyes to burn.
Some doctors and eye care specialists say that after someone complains of blindness after looking at a solar eclipse unaided, they can see what the Sun and moon looked like at the time that they looked at it, as it is burned onto their retinas.
From all the options listed, as seen in the picture attached, the example which best represents the use of creativity in a scientific inquiry is option D. i.e. <span>developing a new way to extract a particular protein from tissue samples. Figuring out new methods and implementing them is what is called as creativity in scientific inquiry.</span>
Answer:
<em><u>Assuming that the vertical speed of the ball is 14 m/s</u></em> we found the given values:
a) V₀ = 23.4 m/s
b) h = 27.9 m
c) t = 0.96 s
d) t = 4.8 s
Explanation:
a) <u>Assuming that the vertical speed is 14 m/s</u> (founded in the book) the initial speed of the ball can be calculated as follows:
![V_{f}^{2} = V_{0}^{2} - 2gh](https://tex.z-dn.net/?f=%20V_%7Bf%7D%5E%7B2%7D%20%3D%20V_%7B0%7D%5E%7B2%7D%20-%202gh%20)
<u>Where:</u>
: is the final speed = 14 m/s
: is the initial speed =?
g: is the gravity = 9.81 m/s²
h: is the height = 18 m
b) The maximum height is:
![V_{f}^{2} = V_{0}^{2} - 2gh](https://tex.z-dn.net/?f=%20V_%7Bf%7D%5E%7B2%7D%20%3D%20V_%7B0%7D%5E%7B2%7D%20-%202gh%20)
![h = \frac{V_{0}^{2}}{2g} = \frac{(23. 4 m/s)^{2}}{2*9.81 m/s^{2}} = 27.9 m](https://tex.z-dn.net/?f=%20h%20%3D%20%5Cfrac%7BV_%7B0%7D%5E%7B2%7D%7D%7B2g%7D%20%3D%20%5Cfrac%7B%2823.%204%20m%2Fs%29%5E%7B2%7D%7D%7B2%2A9.81%20m%2Fs%5E%7B2%7D%7D%20%3D%2027.9%20m%20)
c) The time can be found using the following equation:
![V_{f} = V_{0} - gt](https://tex.z-dn.net/?f=%20V_%7Bf%7D%20%3D%20V_%7B0%7D%20-%20gt%20)
![t = \frac{V_{0} - V_{f}}{g} = \frac{23.4 m/s - 14 m/s}{9.81 m/s^{2}} = 0.96 s](https://tex.z-dn.net/?f=%20t%20%3D%20%5Cfrac%7BV_%7B0%7D%20-%20V_%7Bf%7D%7D%7Bg%7D%20%3D%20%5Cfrac%7B23.4%20m%2Fs%20-%2014%20m%2Fs%7D%7B9.81%20m%2Fs%5E%7B2%7D%7D%20%3D%200.96%20s%20)
d) The flight time is given by:
![t_{v} = \frac{2V_{0}}{g} = \frac{2*23.4 m/s}{9.81 m/s^{2}} = 4.8 s](https://tex.z-dn.net/?f=%20t_%7Bv%7D%20%3D%20%5Cfrac%7B2V_%7B0%7D%7D%7Bg%7D%20%3D%20%5Cfrac%7B2%2A23.4%20m%2Fs%7D%7B9.81%20m%2Fs%5E%7B2%7D%7D%20%3D%204.8%20s%20)
I hope it helps you!