C. Patient info, name of med, dosage & route, special instructions, prescriber’s DEA#, and number of refills
Answer:
the velocity of the bullet-wood system after the collision is 2.48 m/s
Explanation:
Given;
mass of the bullet, m₀ = 20 g = 0.02 kg
velocity of the bullet, v₀ = 250 m/s
mass of the wood, m₁ = 2 kg
velocity of the wood, v₁ = 0
Let the velocity of the bullet-wood system after collision = v
Apply the principle of conservation of linear momentum to calculate the final velocity of the system;
Initial momentum = final momentum
m₀v₀ + m₁v₁ = v(m₀ + m₁)
0.02 x 250 + 2 x 0 = v(2 + 0.02)
5 + 0 = v(2.02)
5 = 2.02v
v = 5/2.02
v = 2.48 m/s
Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s
Answer:f^n=m(a+g)
Explanation:khan academy said
Answer:
θ = 41.80°
Explanation:
Given that
Mach number M= 1.5
We know that
M = u/c
Where c is the velocity of sound and u is the speed of plane
c= 340 m/s
So
u = 1.5 x 340 m/s
u = 510 m/s
We know that
Now by putting the values
θ = 41.80°
So the angle will be 41.80°.
The time (t) it will take for the train to reach to Grenoble is the quotient when the distance (d) is divided by the speed (s). That is,
t = d / s
Substituting the known values,
t = 480 km / 180 km/h
t = 2.667 h
Thus, it will take approximately 2.7 h to reach Grenoble. The answer is letter D.
