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salantis [7]
2 years ago
7

This refers to the ability of the joints to move through a full range of motion

Physics
1 answer:
Sati [7]2 years ago
3 0

Answer:

Flexibility is the ability of a joint or series of joints to move through an unrestricted, pain free range of motion. ... These soft tissues include: muscles, ligaments, tendons, joint capsules, and skin.

Explanation:

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Which of the following is used to answer scientific questions?
Colt1911 [192]
A) Experiments. Opinion polls are used to study people, intuition and imagination are not official studies. Would appreciate brainliest!
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3 years ago
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If you had to choose one device to use with the battery, what would it be? Do you think such a battery could be invented
maw [93]

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a phone because it has longer lasting battery

Explanation:

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The established value for the speed of light in a vacuum is 299,792,458 m/s. What is the order-of-magnitude of this number?
Rom4ik [11]

The order of magnitude is 10⁸ .

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3 years ago
A force of 16.88 n is applied tangentially to a wheel of radius 0.340 m and causes an angular acceleration of 1.20 rad/s2. What
telo118 [61]

Answer:

4.78 kg/m^2.

Explanation:

τ = Iα

Where,

τ = torque, around a defined axis (N∙m)

I = moment of inertia (kg∙m2)

α = angular acceleration

= 1.2 rad/s^2

τ = F * r

= 16.88 * 0.34

= 5.74 N.m

Therefore, I = 5.74/1.2

= 4.78 kg/m2

6 0
3 years ago
A straight wire is aligned east-west in a region where Earth’s magnetic field has magnitude 0.0780 mT and direction 67.1° below
Sergio [31]

Explanation:

It is given that,

Earth's magnetic field, B=0.078\ mT=0.078\times 10^{-3}\ T

Direction of magnetic field, 67.1 degrees below the horizontal, with the horizontal component directed due north.

The magnetic force on the wire per unit length of wire, \dfrac{F}{L}=0.0300\ N/m

(a) The given scenario is shown in the attached figure as :

Using the right hand rule to find the direction of magnetic force on the wire. By using this rule, we get the magnetic force acting on the wire is in upward direction.

(b) Let I is the current flowing in the wire. The magnetic force is given by the following formula as:

F=ILB

I=\dfrac{F}{LB}

I=\dfrac{0.0300}{0.078\times 10^{-3}}

I = 384.61 A

Hence, this is the required solution.

7 0
3 years ago
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