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salantis [7]
2 years ago
7

This refers to the ability of the joints to move through a full range of motion

Physics
1 answer:
Sati [7]2 years ago
3 0

Answer:

Flexibility is the ability of a joint or series of joints to move through an unrestricted, pain free range of motion. ... These soft tissues include: muscles, ligaments, tendons, joint capsules, and skin.

Explanation:

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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees
dolphi86 [110]

Answer:

a) 1.725*10^5 N

b) 3.83*10^3 N

c) i) 173.24 kN

c) ii) 4.57 kN

Explanation:

See the attachment for calculations

6 0
3 years ago
The following three hot samples have the same temperature. The same amount of heat is removed from each sample. Which one experi
melomori [17]

Complete Question:

The following three hot samples have the same temperature. The same amount of heat is removed from each sample. Which one experiences the smallest drop in temperature, and which one experiences the largest drop? Sample A: 4.0 kg of water [c = 4186 J/(kg·C°)] Sample B: 2.0 kg of oil [c = 2700 J/(kg·C°)] Sample C: 9.0 kg of dirt [c = 1050 J/(kg·C°)]

Answer:

A. Smallest B. Largest.

Explanation:

Assuming no heat exchange except for the heat removed from any sample (which we know is the same for the three ones), and that the process is done using only conduction, we can use the equation that relates the heat lost or gained by one object, with the mass of the object and the consequent change in temperature, as follows:

Q = c*m*ΔT, where c, is a proportionality constant called specific heat, which is different for each material.

As we know that the heat removed is the same for the three samples, we can equate the right sides of the equation for each sample, as follows:

cw*mw*ΔTw = co*mo*ΔTo = cd*md*ΔTd

Replacing by the givens, we have:

4.0 kg. 4,186 J/kgºC*ΔT(ºC) = 2.0 kg*2,700 J/kgºC*ΔT(ºC) =9.0kg*1,050J/kgºC*ΔT(ºC)

As the three expressions must be equal each other, it's clear that the unknown term (the drop in temperature) must compensate the product of the mass times the specific heat.

This product is the following for the three samples:

Water: 4.0 kg*4,186 J/kgºC = 16,744 J/ºC

Oil : 2.0 kg*2,700 J/kgºC    = 5,400 J/ºC

Dirt: 9.0 * 1,050 J/kgºC        = 9,450 J/ºC

Clearly, we see that in order to keep the heat exchange equations equal each other, the water must suffer the smallest drop in temperature, and the oil must experience the largest one.

So, the sample A experiencies the smallest drop in temperature, and sample B does the largest one.

5 0
3 years ago
You are standing on the SCALE<br> The scale is on the floor.<br> What are the forces on the SCALE?
ehidna [41]

Answer:

The Normal and Gravitational Force

Explanation:

The normal force pushes up and is between the ground and the scale. The gravitational force is the force exerted on the ground.

3 0
4 years ago
Read 2 more answers
The speed of light in a vacuum is 299,792,458 m/s. Which gives this number in three significant digits? 299,000,000. m/s 2.99 x
dexar [7]

Answer: 2.99(10)^{-8} m/s

Explanation:

When a number is written in scientific notation (representing the number using powers of base ten) it is expressed so that it contains a digit in the place of the units and all other digits after the decimal point, multiplied by the respective exponent.  

Then, the significant figures (or significant digits) will be the digits that are before the power of ten.  

Now, in the case of the number 299,792,458 if we want to write it with three significant digits, we have to write it in scientific notation as:

2.99(10)^{-8}

7 0
3 years ago
Read 2 more answers
A. Group of cross country runners decided to go on an hour and a half run. During the first hour, they ran a total of 13 kilomet
pshichka [43]

Answer:

The average speed for the entire run is 12 km/h.

Explanation:      

The average speed is given by the following equation:

\overline{v} = \frac{d_{T}}{t_{T}}

Where:

d_{T}: is the total distance

t_{T}: is the total time

If during the first hour, they ran a total of 13 kilometers and then, they ran 5.0 kilometers during the next half an hour we have:

d_{T} = 13 km + 5 km = 18 km

t_{T} = 1 h + \frac{1}{2} h = 1.5 h

Hence, the average speed is:

\overline{v} = \frac{d_{T}}{t_{T}} = \frac{18 km}{1.5 h} = 12 km/h

Therefore, the average speed for the entire run is 12 km/h.

I hope it helps you!                                                                                      

3 0
3 years ago
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