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anastassius [24]
3 years ago
8

24. What determines an element's chemical properties? A

Physics
1 answer:
Maurinko [17]3 years ago
3 0

Explanation:

The chemical properties of an element are determined by the configuration of its electrons in orbit around its nucleus. ... See a Periodic Table of the Elements. The number of protons in the nucleus of an atom is its Atomic Number.

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A racing car reaches a speed of 42 m/s. It then begins a uniform negative acceleration, using its parachute and braking system,
NARA [144]

As per the question the initial speed of the car [ u] is 42 m/s.

The car applied its brake and comes to rest after 5.5 second.

The final velocity [v] of the car will be zero.

From the equation of kinematics we know that

                                         v=u+at [ here a stands for acceleration]

                                         0=42 +5.5a

                                         a =\frac{-42}{5.5} m/s^2

                                          a= -7.64 m/s^2

Here a is taken negative as it the car is decelerating uniformly.

We are asked to calculate the stopping distance .

From equation of kinematics we know that

                                              S=ut+\frac{1}{2} at^2  [here S is the distance]

                                                      = 42*5.5 +\frac{1}{2} [-7.64] [5.5]^2 m

                                                       =115.445 m      [ans]  

8 0
3 years ago
How do you solve this???
Tom [10]
Rt= ΣR = 40Ω
Vt= 80V
It= 80V/40Ω= 2A
V1= 15Ω*2A= 30V
V2= 20Ω*2A= 40V
V3= 5Ω*2A= 10V
4 0
3 years ago
Nerve impulses in the human body travel at a speed of about 100 m/s. A 1.6 m tall man accidentally drops a hammer on his toe. Ho
EastWind [94]

time=distance/speed

1.6/100 secs = 0.016secs=16millisecs

4 0
3 years ago
If V has a magnitude of 14 units and the same direction qs a vector 3i+6j+2k find v​
melomori [17]

Answer:

v = 6i + 12j + 4k

Explanation:

Find the magnitude of the direction vector.

√(3² + 6² + 2²) = 7

Normalize the direction vector.

3/7 i + 6/7 j + 2/7 k

Multiply by the magnitude of v.

v = 14 (3/7 i + 6/7 j + 2/7 k)

v = 6i + 12j + 4k

7 0
3 years ago
What will be the final velocity of a rock if we drop it off of a bridge and it strikes the ground 2.8s later (ignoring air resis
mars1129 [50]
Formula for final velocity: Vf= vi+(a*t)
Vi- initial velocity, a=acceleration, t-time

Vf=vi+(at)
Vf= 0+(9.8m/s*2.8s)
Vf= 27.44 m/s

The acceleration of the Earth when dropping something would be 9.8 m/s

Here is an reference that can help you answer problems like these.
Hope this helps and good luck :)

5 0
3 years ago
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